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Yuki888 [10]
2 years ago
8

Help me simplify 15.6 over -3 plz

Mathematics
1 answer:
Assoli18 [71]2 years ago
5 0
It equals -5.2........
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Expand 2(p+q) ??????
soldier1979 [14.2K]

Answer:

2p+2q

Step-by-step explanation:

7 0
2 years ago
In 6 years, John will be 3 times the age he was 2 years ago. What is his current age?
Vladimir79 [104]

Answer:

John is currently 6 years old.

Step-by-step explanation:

2 years ago: x years

Current time: x+2

In 6 years: x+8

EQUATION:

3(x)=x+8= 3x=x+8

(subract x from both sides)

2x=8

x=4

Therefore, John is 6 years old in current time

7 0
2 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
2 years ago
Write an expression of: divide B by 6, then subtract 3 from the result do not simplify any part of the expression
IrinaVladis [17]

Answer:(4-6)-h

Step-by-step explanation:

7 0
2 years ago
Are these lines parallel perpendicular or neither
Natasha_Volkova [10]

Answer:

perpendicular

Step-by-step explanation:

start but putting each line into the standard line format

2x-y=-5

-y=-2x-5

y=2x+5

x+2y=-6

2y=-x-6

y=-(1/2)x-3

if lines are parallel the slopes would be the same. 2 is not equal to -1/2

if lines are perpendicular the slope of one would be the opposite inverse of the other.

negative inverse of 2 = - (1/2)

so the lines are perpendicular

8 0
3 years ago
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