Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test

Formula : 


Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
Answer:
Step-by-step explanation:
y = (40000)0.95^t
t = time in years
4.5 is the answer.
First you multiply 9.6x3.2 which gives us 30.72
Then you divide 138.24 by 30.72 which equals 4.5
Hope this helps
Answer:
6.32
Step-by-step explanation:
Also known as 2√10
After we solve that we get 6.32455532
we then focus on these numbers here
6.3<em>24</em>55532
It doesnt round up stays the same so we get 6.32 to nearest hundredth