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3 years ago

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What is the length of AC?

1 answer:

lora16 [44]3 years ago

5 0

Answer:

the answer is 18 feet because that line in the middle of the triangle is half the size of AC

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Can some one give me a helping hand

kati45 [8]

There is one negative number. Do you think the answer is a negative, out of the answer choices they gave you? it could be a positive. I DON'T know the answer. This is just a tip for you

5 0

3 years ago

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

Can y’all help with this :)))))

cricket20 [7]

There’s a pattern to this and I’ll explain in the comments if you want to know or can’t figure it out :)

1.) 27/x^3

2.) a^8/b^12

3.) 7^36/81 OR 13,841,287,201/81

4.) 256m^20/n^4

5.) x^6y^6

6.) 64k^4/k^6

7.) 1,000a^9b^6/a^6b^9

8.) 81x^21/625

9.) 2304/x^16y^12

10.) x^7z^14/y^21

11.) 7,776k^5

12.) x^24y^24/4,096

Hope it’s all helped

7 0

3 years ago

PLEASE HELP PLEASE PLEASE

AysviL [449]

Answer:

A. March

Step-by-step explanation:

You can tell by subtracting the tallest bar in the month from the shorter one, and seeing which number is bigger out of all of them.

Hope this helped :)

5 0

2 years ago

Read 2 more answers

Please help it is multiple choice

Natalka [10]

Answer:

1/2

Step-by-step explanation:

4 0

3 years ago