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ahrayia [7]
3 years ago
8

Mrs. Galindo decided to make Kool-Aid to serve along with the pizza at the Future Farmers of America party. The directions said

to mix a half of a scoop of powdered drink mix with two gallons of water to make each pitcher of Kook-Aid. One of Mrs. Galindo's students said she will mix 4 scoops with 2 gallons of water to make 4 pitchers. Which choice best explains whether the student is correct and why. Question 1 options: The direction's constant of proportionality is 4. k = 2/0.5 There are 4 gallons of water per one scoop. The student is correct because 4 pitchers = 4 scoops times 2 gallons The direction's constant of proportionality is 4. k = 2/0.5 There are 4 gallons of water per one scoop. The student is incorrect because 4 pitchers does not equal 4 scoops times 2 gallons The direction's constant of proportionality is 0.25 k = 0.5/4 There is a quarter of a gallon of water per one scoop The student is correct because 4 pitchers = 4 scoops times 2 gallons The student is incorrect because 4 pitchers does not equal 4 scoops times 2 gallons
Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

The direction's constant of proportionality is 4. k = 2/0.5 There are 4 gallons of water per one scoop. The student is incorrect because 4 pitchers does not equal 4 scoops times 2 gallons

Step-by-step explanation:

Direction :

1/2 of a scoop + 2 gallons = 1 pitcher

Mrs. Galindo's students:

4 pitcher = 4 scoops + 2 gallons of water

Correct mixture for 4 pitchers:

1/2 scoop + 2 gallons of water =1 pitcher

For 4 pichers, multiply both sides by 4

1/2(4) scoops + 2(4) gallons of water =4 pitchers

4/2 scoops + 8 gallons of water =4 pitchers

2 scoops + 8 gallons of water =4 pitchers

The direction's constant of proportionality is 4. k = 2/0.5 There are 4 gallons of water per one scoop. The student is incorrect because 4 pitchers does not equal 4 scoops times 2 gallons

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(x-4)²/16 + (y-8)²/25 = 1

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What is the rate of change?
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Directions: Determine the area of the shaded region of each figure. The polygons in each problem are regular polygons. You must
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Problem 1

Imagine placing the nonpencil part of your compass at the center of both hexagons. Extend the compass so the pencil reaches the right-most point on the larger hexagon. Then sweep a full 360 degrees to form a circle. This surrounds the larger hexagon to form what is called the circumcircle. The circumradius is 6+6 = 12 feet.

If we know the circumradius r = 12 and the number of sides n = 6, then we can find the area of the larger regular hexagon using this formula

A = 0.5n*r^2*\sin(360/n)

Your calculator must be in degree mode. This formula only works for regular polygons.

Let's use that formula to calculate the area of the larger regular hexagon.

A = 0.5n*r^2*\sin(360/n)\\\\A = 0.5*6*12^2*\sin(360/6)\\\\A \approx 374.122974

Then do the same for the smaller regular hexagon that has circumradius of r = 6 this time. We still have n = 6 sides.

A = 0.5n*r^2*\sin(360/n)\\\\A = 0.5*6*6^2*\sin(360/6)\\\\A \approx 93.530744

Now subtract the areas

374.122974-93.530744 = 280.59223

<h3>The green region has an area of roughly 280.59223 square feet.</h3>

=========================================================

Problem 2

The formula we use here is

A = 0.25n*s^2*\cot(180/n)

where

  • n = number of sides = 5 in this case for both figures
  • s = side length = will be different values depending on which figure you focus on
  • "cot" refers to the cotangent function, which is the reciprocal of tangent. Your calculator should support cotangent. If not, then you'd have to do 1/tan of the value of 180/n. In this case, n = 5 so 180/n = 180/5 = 36. So you either calculate cot(36) or 1/tan(36)
  • Your calculator must be in degree mode.
  • This formula only works on regular polygons. These are polygons with the same side lengths and same angles.

Let's use that formula to calculate the area of the larger regular pentagon. It has side lengths of s = 8

A = 0.25n*s^2*\cot(180/n)\\\\A = 0.25*5*8^2*\cot(180/5)\\\\A = 0.25*5*8^2*\cot(36)\\\\A = 0.25*5*8^2*\frac{1}{\tan(36)}\\\\A \approx 110.110554\\\\

The larger regular pentagon has area of roughly 110.110554 square cm.

Repeat those steps for the smaller pentagon where each side is now s = 6. Keep n = 5 the same.

A = 0.25n*s^2*\cot(180/n)\\\\A = 0.25*5*6^2*\cot(180/5)\\\\A = 0.25*5*6^2*\cot(36)\\\\A = 0.25*5*6^2*\frac{1}{\tan(36)}\\\\A \approx 61.937186\\\\

Now subtract the two areas to get the area of the shaded green region.

110.110554 - 61.937186 = 48.173368

<h3>The green region has area of roughly 48.173368 square cm.</h3>
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