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Talja [164]
3 years ago
14

True or false: when an ospf route sends its link state information, it is sent only to those nodes directly attached neighbors.

explain.
Computers and Technology
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

The following statement is True.

Explanation:

LSU(Link State Update) is also known as the Link State Acknowledgements.  

Link State Update packets are use for flooding of the Link State Acknowledgements and sending Link State Acknowledgement response to the Link State Request packets.  

It sent directly connected neighbors who previously requested the Link State Acknowledgements in form of the Link State Request packets.  

In the case of the flooding, neighbors routers are only responsible for the re-encapsulation of the received Link State Acknowledgement informations in the new Link State Update packets.

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Why is outfitting a workspace with video games in technology development company considered a strategic use of money
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4 years ago
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Not all products are well suited for sale on the internet. T or F
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3 years ago
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write a loop that reads positive integers from standard input and that terminates when it reads an integers that is not positive
rjkz [21]
I found this loop. But it ends like this: After the loop terminates, <span>it prints out the sum of all the even integers read. Declare any variables that are needed.</span>

<span>int sum=0;
int num=1;
while(num > 0){
cin >> num;
if ((num % 2)==0 & (num>0)){
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7 0
3 years ago
Create a string called alphabet containing 'abcdefghijklmnopqrstuvwxyz', then perform the following separate slice operations to
spin [16.1K]

Answer:

There is no short answer.

Explanation:

First let's create the string:

  • alphabetString = "abcdefghijklmnopqrstuvwxyz";

The first half of the string using slice method can be written as:

  • alphabetString.slice(0, 13);

The first half of the string using only the ending index can be written as:

  • alphabetString.slice(-13);

When we put - at the start of the index number, the counting begins at the last element with -1 and goes backwards.

The second half of the string can be written as:

  • alphabetString.slice(13,26);

The second half of the string using only the starting index can be written as:

  • alphabetString.slice(13);

To get the every second letter in the string, we need a for loop:

  • for( let x = 0; x < alphabetString.length(); x = x + 2){

                 alphabetString.slice(x);

}

To get the entire string in reverse, we can use the reverse method that is built-in:

  • alphabetString.reverse();

To get the every third letter of the string, we can again use a for loop:

  • for( let x = -1; x = -27; x = x - 3){

                  alphabetString.slice(x);

}

I hope this answer helps.

7 0
4 years ago
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