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Consider the function f(x) = (x − 3)2(x + 2)2(x − 1). The zero has a multiplicity of 1. The zero −2 has a multiplicity of .
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Multiply each term in the parentheses, namely 2/3 and 3x, by the only term outside of the parentheses, -4.
Each of the resulting products becomes a new term in the addition.
You may choose to keep the answer this way, or continue to change the improper fraction into a proper fraction. A lot of teachers also prefer to have the highest degree terms (terms that have variables with the highest powers) on the left.