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almond37 [142]
4 years ago
6

Two snow resorts offer private lessons to their customers. Big Time Ski Mountain charges $6 per hour plus $50 insurance. Powder

Hills charges $10 per hour plus $30 insurance. For what number of hours is the cost of lessons the same for each resort
Mathematics
1 answer:
Agata [3.3K]4 years ago
4 0
So add $50 +$30+$10+$6 U will get $96
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Kiran wrote f(x) = (x − 3)(x - 7) as an example of a function whose graph has x-
bezimeni [28]
The x intercepts were supposed to be x = 3, 7
7 0
4 years ago
A linear function has the same y-intercept as x + 4y = 8 and its graph contains the point (4, 3). Fill in the blank to find the
melamori03 [73]

Answer:

The y - intercept is (0, 4)

Step-by-step explanation:

The equation x + 4y = 8 is in 'standard form.'  Any line parallel to this line has an equation that looks exactly the same EXCEPT for the constant.

So, let's write out x + 4y = 8 and replace the 8 with C.

x + 4y = C

Now take the coordinates of the given point (4, 3) and substitute them into the above equation:  4 + 4(3) = C = 16

Thus, the equation of the line passing through (4, 3) is x + 4y = 16.

To find the y-intercept, set x = 0 and calculate y:

0 + 4y = 16, or y = 4

The y - intercept is (0, 4)

5 0
4 years ago
How to solve 8,725+w=10,619
tigry1 [53]
You subtract 8,725 to the other side so the problem would be w=10,619-8,725 and the answer would be W=1,894
3 0
4 years ago
Read 2 more answers
Someone help me please
RoseWind [281]

9514 1404 393

Answer:

  • A = (0, 1)
  • B = (3, -2)
  • area = 4.5 square units

Step-by-step explanation:

Rewriting the equations to make x the subject, we have ...

  x = y² -1 . . . . . [eq1]

  x = 1 - y . . . . . .[eq2]

At the points of intersection, the difference will be zero.

  y² -1 -(1 -y) = 0

  y² +y -2 = 0

  (y -1)(y +2) = 0

The y-coordinates of points A and B are 1 and -2.

The corresponding x-coordinates are ...

  x = 1 -{1, -2} = {1 -1, 1+2} = {0, 3}

Then A = (0, 1) and B = (3, -2).

__

A differential of area can be written ...

  (x2 -x1)dy = ((1 -y) -(y² -1))dy = (2 -y -y²)dy

Integrating this over the interval y = [-2, 1] gives the area.

  \displaystyle A=\int_{-2}^1(2-y-y^2)\,dy=\left.(2y-\dfrac{1}{2}y^2-\dfrac{1}{3}y^3)\right|_{-2}^1\\\\=\left(2-\dfrac{1}{2}-\dfrac{1}{3}\right)-\left(2(-2)-\dfrac{(-2)^2}{2}-\dfrac{(-2)^3}{3}\right)=\dfrac{7}{6}+4+2-\dfrac{8}{3}\\\\=\boxed{4.5}

The area of the shaded region is 4.5 square units.

5 0
3 years ago
Can someone help me with this, please?
steposvetlana [31]

Answer:

80, 96, 8, 10

Step-by-step explanation:

The first set gives us the ratio, 32:2 which is basically 16

5*16= 80

6*16= 96

Notice how it is on the top now, so divide by 16

128/16= 8

160/16=10

6 0
3 years ago
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