Question

Find the sum of the first 8 terms of the geometric series, if the first term is 3 and the common

Answer 1

Answer:

65535

Step-by-step explanation:

The sum to n terms of a geometric sequence is

$S_{n}$ = $\frac{a(r^n-1)}{r-1}$

where a is the first term and r the common ratio, thus

$S_{8}$ = $\frac{3(4^8-1|)}{4-1}$

                        = $\frac{3(4^8-1)}{3}$

                        = $4^{8}$ - 1 = 65536 - 1 = 65535