If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
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Step-by-step explanation:
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C) 12√2
Step-by-step explanation:
According to the 45-45-90 triangle x should be a√2 and since a = 12 (in this case) the answer is 12√2.
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110
Step-by-step explanation:
The answer is 110 degrees. The reason is hard to put into simple language.
If the central angle and the acute angle hitting the circumference share the same end points, then the central angle is double the arc whose vertex is on the circumference.
Read that sentence a couple of times. I don't know how to make it simpler.
The arc angle and the central angle both have B and C as their end points.
The arc angle is on the circumference of the circle. The vertex (A) of BAC is on the circumference. If mine is the only answer, wait a few days before awarding a Brainliest. A thanks will do.