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iris [78.8K]
2 years ago
14

A rectangular prism measures 3ft by 6ft by 5ft. If the dimensions of the box were all quadrupled. How would the surface area of

the box change?
Mathematics
1 answer:
Blababa [14]2 years ago
3 0

The surface area of a shape is the amount of space on the shape

When the dimensions are quadrupled, the new surface area would be 16 times the initial surface area

<h3>How to determine the surface area</h3>

The surface area of a rectangular prism is:

S = 2 * (lw + lh + wh)

When quadrupled, we have:

S_2 = 2 * (16lw + 16lh + 16wh)

Factor out 16

S_2 =16 * 2 * (lw + lh + wh)

Substitute S = 2 * (lw + lh + wh)

S_2 =16 * 2 * S

The above means that:

The new surface area would be 16 times the initial surface area

Read more about surface areas at:

brainly.com/question/24571594

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Answer:

the answer is G

which is 6.2*10 to the 9th power.

Step-by-step explanation:

In scientific notation you must leave one digit to the place value of ones

so that one digit is 6

So ue come up with 6.2 when ue eliminate all other zeros and end the decimal point between 6 and 2 and that way you have 6.2*10 to the 9th power

6 0
3 years ago
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Factorize: x² + 3x + 2​
zvonat [6]

Step-by-step explanation:

x² + 3x + 2

x² + x + 2x + 2 because 1+2=3 and 2×1=2

By taking out common terms, we get

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7 0
3 years ago
Triangles abc, dbe, and fbg are all symmetric about the y-axis. what are the coordinates of the centroid?
Drupady [299]

Answer:

The coordinates of the centroid are (0, 5)

Step-by-step explanation:

The coordinates of the centroid of a triangle whose vertices (x1, y1), (x2, y2), and (x3, y3) are (\frac{x1+x2+x3}{3} , \frac{y1+y2+y3}{3})

In Δ ABC

∵ A = (-20, 0), B = (0, 15), C = (20, 0)

∴ x1 = -20, x2 = 0, x3 = 20

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = (\frac{-20+0+20}{3} , \frac{0+15+0}{3}) = (\frac{0}{3} , \frac{15}{3}) = (0, 5)

∴ The coordinates of the centroid of Δ ABC are (0, 5)

In Δ DBE

∵ D = (-15, 0), B = (0, 15), E = (15, 0)

∴ x1 = -15, x2 = 0, x3 = 15

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = (\frac{-15+0+15}{3} , \frac{0+15+0}{3}) = (\frac{0}{3} , \frac{15}{3}) = (0, 5)

∴ The coordinates of the centroid of Δ DBE are (0, 5)

In Δ FBG

∵ F = (-5, 0), B = (0, 15), G = (5, 0)

∴ x1 = -5, x2 = 0, x3 = 5

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = (\frac{-5+0+5}{3} , \frac{0+15+0}{3}) = (\frac{0}{3} , \frac{15}{3}) = (0, 5)

∴ The coordinates of the centroid of Δ FBG are (0, 5)

∵ The three triangles are symmetric about the y-axis

→ That means they have the same centroid and it lies on the y-axis

∴ The coordinates of the centroid are (0, 5)

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2 years ago
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Please help, it's due in less then 30 minutes :')​
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Answer:

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Step-by-step explanation:

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