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trasher [3.6K]
4 years ago
15

What two positive real numbers whose product is 21 have the smallest possible​ sum?

Mathematics
1 answer:
GalinKa [24]4 years ago
3 0

Answer:

x=\sqrt{21}

y=\sqrt{21}

Step-by-step explanation:

Let x  and y are the two positive real numbers

product of two numbers is 21

x y=21

y=\frac{21}{x}

The sum of the two numbers is f(x) =x+y

Replace y with 21/x

f(x) =x+\frac{21}{x}

we need to find smallest possible sum , so we take derivative using power rule

f'(x)= 1-\frac{21}{x^2}

when sum is minimum then the derivative is equal to 0

0= 1-\frac{21}{x^2}

0=\frac{x^2-21}{x^2}

multiply both sides by x^2

x^2-21=0

x^2=21

Take square root on both sides

x=\sqrt{21}

y=\frac{21}{x}

y=\frac{21}{\sqrt{21}}

y=\sqrt{21}

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What is the fewest number of points you must plot in order to have examples of all four sets of​ numbers, including at least one
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Answer:

Let's define the sets:

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Then:

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4 years ago
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Simultaneous Equations

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4u + 3b = $268

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b = $48

If you want to find out what a unicycle costs...
Substitute b = $48 into the first equation
2u + $48 = $110
Balance the equation, whatever happens on one side, happens on the other.
2u + $48 (-$48) = $110 (-$48)
2u = $62
2u(/2) = $62(/2)
u = $31 
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