Value of k=4
5(4)=20
2(4)=8
20-8=12
Answer:
The answer is row C
Step-by-step explanation:
6 - 3 = 3
Let's
simplify step-by-step.
3x2(x2−4x−4)+5x3+7x2+2x+11
Distribute:
=(3x2)(x2)+(3x2)(−4x)+(3x2)(−4)+5x3+7x2+2x+11
=3x4+−12x3+−12x2+5x3+7x2+2x+11
Combine
Like Terms:
=3x4+−12x3+−12x2+5x3+7x2+2x+11
=(3x4)+(−12x3+5x3)+(−12x2+7x2)+(2x)+(11)
=3x4+−7x3+−5x2+2x+11
Answer:
=3x4−7x3−5x2+2x+11
<span> </span>
Answer:
B
Step-by-step explanation:
CosA = AB/AC = 12/20 = 3/5
Answer:
a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.
Step-by-step explanation:
Question a:
20% of employees engage in physical exercise.
This 20% is composed by:
8% of 60%(males)
x% of 100 - 60 = 40%(females).
Then, x is given by:




0.38 = 38%
Probability of being a female who engages in exercise:
40% are female, 38% of 40% engage in exercise. So
0.38*0.4 = 0.152
0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?
40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So
0.62*0.4 = 0.248
0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.