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damaskus [11]
3 years ago
11

Determine which of the following points lies on the line y= 5/4 x + 2

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
3 0
The point (4,7) is the only one that can be plugged into the equation and work. in this case when 4 is plugged in as X & Y is plugged in at 7 we get that 7=7, which is a true statement.
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What is the value of k in the equation 5k-2k=12
kenny6666 [7]
Value of k=4
5(4)=20
2(4)=8
20-8=12
3 0
4 years ago
Need help asap please
Lelechka [254]

Answer:

The answer is row C

Step-by-step explanation:

6 - 3 = 3

3 0
3 years ago
3x^2 (x^2 - 4x - 2) + (5x^3 + 7x^2+2x+11) plz show work
matrenka [14]

Let's simplify step-by-step.

3x2(x2−4x−4)+5x3+7x2+2x+11

Distribute:

=(3x2)(x2)+(3x2)(−4x)+(3x2)(−4)+5x3+7x2+2x+11

=3x4+−12x3+−12x2+5x3+7x2+2x+11

Combine Like Terms:

=3x4+−12x3+−12x2+5x3+7x2+2x+11

=(3x4)+(−12x3+5x3)+(−12x2+7x2)+(2x)+(11)

=3x4+−7x3+−5x2+2x+11

Answer:

=3x4−7x3−5x2+2x+11

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5 0
4 years ago
Need to find the ratio
wolverine [178]

Answer:

B

Step-by-step explanation:

CosA = AB/AC = 12/20 = 3/5

6 0
3 years ago
Suppose that 20% of the employees of a given corporation engage in physical exercise activities during the lunch hour. Moreover,
Harlamova29_29 [7]

Answer:

a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

Step-by-step explanation:

Question a:

20% of employees engage in physical exercise.

This 20% is composed by:

8% of 60%(males)

x% of 100 - 60 = 40%(females).

Then, x is given by:

0.08*0.6 + 0.4x = 0.2

0.4x = 0.2 - 0.08*0.6

x = \frac{0.2 - 0.08*0.6}{0.4}

x = 0.38

0.38 = 38%

Probability of being a female who engages in exercise:

40% are female, 38% of 40% engage in exercise. So

0.38*0.4 = 0.152

0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?

40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So

0.62*0.4 = 0.248

0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

3 0
3 years ago
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