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damaskus [11]
3 years ago
11

Determine which of the following points lies on the line y= 5/4 x + 2

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
3 0
The point (4,7) is the only one that can be plugged into the equation and work. in this case when 4 is plugged in as X & Y is plugged in at 7 we get that 7=7, which is a true statement.
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diamong [38]
I think it’s A Im not completely sure tho.
3 0
2 years ago
help asap! Write an expression equivalent to [5x²]-[15x] that is a product of two expressions. Fill in the blanks with numbers,
adoni [48]

Answer: 5x (x-3) or 5(x^2-3x)

Step-by-step explanation:

3 0
3 years ago
Does anyone know what this is?
Amiraneli [1.4K]
The v means the square root I hope this helps
5 0
2 years ago
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
Vikki [24]

Answer:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

Step-by-step explanation:

Information given:

n=131 represent the sample size

\hat p=0.81 represent the estimated proportion

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.326

And replacing into the confidence interval formula we got:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

6 0
3 years ago
Multiply and combine like terms. Use^for exponents. (2x-6) (3x-2)<br>​
Georgia [21]

Answer:

Expand the polynomial using the FOIL method.

6x2−22x+12

Step-by-step explanation:

5 0
3 years ago
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