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Ghella [55]
3 years ago
5

What is the common ratio in the following geometric sequence?

Mathematics
1 answer:
sesenic [268]3 years ago
7 0

Answer:

Correct answer:  q = 4

Step-by-step explanation:

Given:

3, 12, 48, 192, .....

First term       b₁ = 3

Second term b₂ = 12

Third term     b₃ = 48

Fourth term   b₄ = 192

Common ratio or quotient is:

q = b₂ / b₁ = b₃ / b₂ = 12 / 3 = 48 / 12 = 4

q = 4

God is with you!!!

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alekssr [168]
4.2 because it has a box around the corner that makes it whole
4 0
2 years ago
HELPPP ASAPPPPP!!!!!! PLEASE :(
goldfiish [28.3K]

Step-by-step explanation:

A bar graph serves to visibly represent the frequency of a series of events.

To create a bar graph you can draw on the horizontal axis, each one of the events, and on the axis to verticate the frequency of occurrence.

For this case the possible events are the values from 1 to 5 of the numbered sequence

1 2 3 4 5

The frequency for each number is

4 6 2 6 2.

With these values, a bar graph was made in excel, which is shown in the attached image.

There it is observed that the events with greater frequency are the 4 and the 2.


5 0
3 years ago
It’s confusing, would the answer be square root 7 over 4?
Colt1911 [192]

Answer:

\tan U = 1

Step-by-step explanation:

\text{Apply Pythagorean theorem,}\\\\~~~~~~\text{Hypotenuse}^2 = \text{Base}^2 + \text{Perpendicular}^2\\\\\implies UT^2 = UV^2 +VT^2\\\\\implies UV^2 = UT^2 -VT^2\\\\\implies UV^2 = \left(7\sqrt 2 \right)^2 - 7^2\\\\\implies UV^2 = 49(2)-49\\\\\implies UV^2 = 49\\\\\implies UV = \sqrt{49} \\\\ \implies UV = 7

\text{Now,}\\\\~~~~~~~~\tan \theta = \dfrac{\text{Perpendicular}}{\text{Base}}\\\\\\\implies \tan U = \dfrac{7}{7}\\\\\\\implies \tan U = 1

4 0
2 years ago
Here's a question ~
Gre4nikov [31]

Answer:

  • (0, 5√3/2 + 2)

Step-by-step explanation:

Given is the absolute value function.

<u>Observations:</u>

  • It has a slope of ±√3 and the y- intercept of 2.
  • There is no horizontal shift, so the the y-axis is the line of symmetry.
  • The y-axis is also an angle bisector of the two lines.
  • The foot P₁P₂ is parallel to the x-axis since it's perpendicular to the y- axis.

We need to find the coordinates of intersection of the line P₁P₂ with the y- axis (the point Y in the picture).

Consider the triangle AYP₂.

We know AP₂ = 5.

<u>The angle YAP₂ is:</u>

  • arctan (1/√3) = 30°

<u>The distance AY is:</u>

  • AY = AP₂ cos 30° = 5*√3/2

<u>The distance from the x-axis to the point Y is:</u>

  • 5√3/2 + 2, added the y- intercept of the graphed lines

<u>The coordinates of the point Y:</u>

  • (0, 5√3/2 + 2)

3 0
3 years ago
Two dice are rolled. Use the complement rule to find that the probability that the sum of the dice is less than 10.
Katarina [22]

Answer:

\dfrac{5}{6}

Step-by-step explanation:

When two dice are rolled, the sample space is

\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}

In total, 36 outcomes

First, find the probability that the sum is 10 or greater:

All favorable outcomes

10: (4,6),\ (5,5),\ (6,4)

11: (5,6),\ (6,5)

12: (6,6)

In total, 6 outcomes.

The probability that the sum is 10 or greater is

P(A)=\dfrac{6}{36}=\dfrac{1}{6}

Use the complement rule to find that the probability that the sum of the dice is less than 10:

P(A^C)=1-P(A)=1-\dfrac{1}{6}=\dfrac{5}{6}

6 0
3 years ago
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