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Ghella [55]
3 years ago
5

What is the common ratio in the following geometric sequence?

Mathematics
1 answer:
sesenic [268]3 years ago
7 0

Answer:

Correct answer:  q = 4

Step-by-step explanation:

Given:

3, 12, 48, 192, .....

First term       b₁ = 3

Second term b₂ = 12

Third term     b₃ = 48

Fourth term   b₄ = 192

Common ratio or quotient is:

q = b₂ / b₁ = b₃ / b₂ = 12 / 3 = 48 / 12 = 4

q = 4

God is with you!!!

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If f(x)f(x) is an exponential function where f(1.5)=5f(1.5)=5 and f(7.5)=79f(7.5)=79, then find the value of f(3)f(3), to the ne
stiv31 [10]

Answer: 7.93

Step-by-step explanation:

Given

f(x) is an exponential function. Suppose f(x) is ae^{bx}

f(1.5)=5\ \text{and}\ f(7.5)=79

\Rightarrow 5=ae^{1.5b}\\\Rightarrow \ln 5=\ln a-1.5b\quad \ldots(i)

Similarly,

\Rightarrow 79=ae^{7.5b}\\\Rightarrow \ln(79)=\ln a+7.5b\quad \ldots(ii)

Subtract (i) and (ii)

\Rightarrow \ln (79)-\ln (5)=9b\\\Rightarrow \ln (\frac{79}{5})=9b\\\\\Rightarrow b=\dfrac{\ln (\frac{79}{5})}{9}\\\\\Rightarrow b=0.3066

Insert the value of b

\Rightarrow 5=ae^{0.46}\\\Rightarrow a=5\times 0.6312\\\Rightarrow a=3.156\approx 3.16

So, the function becomes

\Rightarrow f(x)=3.16e^{0.3066b}

\Rightarrow f(3)=3.16e^{0.3066\times 3}\\\Rightarrow f(3)=7.927\approx 7.93

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3 years ago
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