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3 years ago

Helpppp meeee question 1 pleaseee !!!

Mathematics

2 answers:

crimeas [40]3 years ago

6 0

Answer:

2,0,-2,-4

Step-by-step explanation:

For example

-2 x -3 = 6

6 - 4 = 2

-2 x -3 - 4 = 2

-2x - 4

love history [14]3 years ago

4 0

Answer:

2 0 -2 -4

Step-by-step explanation:

pls give brainliest

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Solving x+ 8 = –3 gives: (i) x = 11 (ii) x = 12 (iii) x = –11 (iv) x = –12

olchik [2.2K]

Answer:

x+8=-3 gives

x=-11 is the required value

8 0

2 years ago

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What is the negative of -1/4

Vlad1618 [11]

The negative of it would be the positive so the answer is 1/4

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3 years ago

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A researcher is investigating whether a new fertilizer affects the yield of tomato plants. As part of an experiment, 20 plants w

IgorLugansk [536]

Answer:

Correct option is (c).

Step-by-step explanation:

The experiment is conducted to determine whether a new fertilizer affects the yield of tomato plants.

The procedure involves randomly assigning the new fertilizer to 20 plants and the other 20 will be assigned the current fertilizer.

Then the mean number of tomatoes produced per plant will be recorded for each fertilizer, and the difference in the sample means will be calculated.

The collected sample data will then be used to make conclusion about the population.

The researchers main aim is to determine whether the new fertilizer is effective or not, i.e. if on using the new fertilizer the yield of tomatoes increases or not.

So, the parameter under study id the difference between tow population means.

To make inferences about the experiment the researcher can construct a two-sample t-interval for a difference between population means. The confidence interval has a certain specific probability of including the true parameter value.

Thus, the correct option is (c).

4 0

3 years ago

What is 23/1 divided by 9/2

hoa [83]

$\frac{\frac{23}{1}}{\frac{9}{2}}=\ \ \ \ | multiply\ first\ fration\ by\ inverse\ of\ the\ second\\\\
\frac{23}{1}*\frac{2}{9}=\frac{46}{9}=5\frac{1}{9}\\\\
Solution\ is\ 5\frac{1}{9}.$

3 0

3 years ago

Find the function y1 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y1(0)=1,y′1(0)=0. y1= Note: y1 is

strojnjashka [21]

Answer:

Step-by-step explanation:

The original equation is $121y''+110y'-24y=0$ . We propose that the solution of this equations is of the form $y = Ae^{rt}$ . Then, by replacing the derivatives we get the following

$121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)$

Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that

$121r^2+110r-24=0$

Recall that the roots of a polynomial of the form $ax^2+bx+c$ are given by the formula

$x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}$

In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions

$r_1 = -\frac{12}{11}$

$r_2 = \frac{2}{11}$

So, in this case, the general solution is $y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}$

a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations

$c_1 + c_2 = 1$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 0$ (or equivalently $c_2 = 6c_1$

By replacing the second equation in the first one, we get $7c_1 = 1$ which implies that $c_1 = \frac{1}{7}, c_2 = \frac{6}{7}$ .

So $y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}$

b) By using y(0) =0 and y'(0)=1 we get the equations

$c_1+c_2 =0$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 1$ (or equivalently $-12c_1+2c_2 = 11$

By solving this system, the solution is $c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}$

Then $y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}$

The Wronskian of the solutions is calculated as the determinant of the following matrix

$\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2$

By plugging the values of $y_1$ and

We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by

$e^{\int -p(x) dx}$

In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is

$e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}$

Note that this function is always positive, and thus, never zero. So $y_1, y_2$ is a fundamental set of solutions.

8 0

2 years ago