The answer to your question would be A
Answer:
D the horizontal cross-section of the pyramid and cone at the same height must have the same area
Answer:
I'd need to see more, but because they are the same number just positive and negative they'd be on opposite ends of zero
Josh has hiked 17 km, which is 2 km away from being 1/2 done. You are welcome!
The sides of the triangle are 20 in, 48 in and 52 in
<u>Explanation:</u>
Given:
Let x be the length of smaller leg
Hypotenuse, H = x + 32
Height, h = x + 28
Length of the sides of a triangle = ?
If the triangle is a right angle triangle then we use pythagoras theorm to solve the question.
So,
(Hypotenuse)² = (height)² + (Base)²
(x + 32)² = (x + 28)² + (x)²
x² + 1024 + 64x = x² + 784 + 56x + x²
240 + 8x - x² = 0
x² - 8x - 240 = 0
Solving the quadratic equation:
x² + 12x - 20x - 240 = 0
x(x+12) - 20(x+12) = 0
(x-20) (x+12) = 0
(x-20) = 0
x = 20 in
Hypotenuse, H = x + 32
H = 20 + 32 in
H = 52 in
Height, h = x + 28
h = 20 + 28 in
h = 48 in
Therefore, the sides of the triangle are 20 in, 48 in and 52 in