All categories

3 years ago

Can some please helppp!!!!

Mathematics

2 answers:

WINSTONCH [101]3 years ago

7 0

Answer:

right scalene

Step-by-step explanation:

The triangle above it has a right degree angle which makes that triangle a right triangle because it shares the same line.

it is scalene because there are no angles or side that are equal to each other

BigorU [14]3 years ago

4 0

The answer should be acute and scalene. Sorry if I’m wrong though

You might be interested in

Y=6x+20 substitution

Oksana_A [137]

Answer:

-10/3 or -3.33

Step-by-step explanation:

substitute 0 for y

0 = 6x + 20

-20 = 6x + 20 - 20 subtract 20 on both sides

-20 = 6x divide by 6 on each side

-20/6 = 6x/6

x = -20/6 simplify

x = -10/3

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%3Cbr%3E%0Ay%3D%20x%5E%7B2%7D%20-9" id="TexFormula1" title="&#10;y= x^{2} -9" alt="&#1

svp [43]

Simple...

y= $x^{2} -9$

$y= x^{2} -9$

It's quite easy to see $x^{2} = x^{2}$

Thus, any value of x makes the equation true.

Thus, your answer.

7 0

3 years ago

What is the sum of i° + k°?

Brut [27]

Answer

1 + 32 + 243 + 1024 + .. + n5

Step-by-step explanation:

8 0

3 years ago

If f(x)=ln(sin(2x)), f''(π/4) is equal to

Licemer1 [7]

Use the chain rule to compute the second derivative:

$f(x)=\ln(\sin(2x))$

The first derivative is

$f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}$

$f'(x)=2\cot(2x)$

Then the second derivative is

$f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'$

$f''(x)=-4\csc^2(2x)$

Then plug in π/4 for <em>x</em> :

$f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4$

4 0

3 years ago

Convert 86 degrees Fahrenheit to degrees celsius

dybincka [34]

86 degrees Fahrenheit is 30 degrees Celsius

3 0

3 years ago

Read 2 more answers