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LuckyWell [14K]
3 years ago
12

What word phrase can you use to represent the algebraic expression 7x?

Mathematics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

7 times x

Step-by-step explanation:

When the expression is seen, we can say that it displays 7 times x.

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What is 2(3t-1)-5(t-1)
givi [52]
2(3t - 1) - 5(t - 1)
2(3t) - 2(1) - 5(t) + 5(1)
6t - 2 - 5t + 5
6t - 5t - 2 + 5
t + 3
3 0
4 years ago
A ball is shot straight up into the air from the ground with initial velocity of 45ft/sec. Assuming that the air resistance can
Nesterboy [21]
V2^2 = V1^2 - 2gh 

<span>=> 0 = 44^2 - 2 (32.2) h </span>

<span>=> h = 44^2 / 64.4 = 30.062 ft</span>
6 0
3 years ago
Andrea is designing the seating arrangement for a concert in her local park. to give everyone a good view, each row must have 4
RideAnS [48]

Andrea is designing the seating arrangement for a concert in her local park. The number of seats in row 20 would be 86 seats.

<h3>What is the Arithmetic Sequence?</h3>

Arithmetic sequence is a sequence where each consequtive term has a common constant difference.

An arithmetic sequence, therefore, is defined by two parameters, viz. the starting term and the common difference.

The arithmetic sequence formula is;

aₙ = a + (n − 1)d,

where;

a is the first term

n is the position of the term in the sequence

d is the common difference

aₙ  is the nth term of the sequence.

Our sequence is 10, 14, 18, 22 up to row 20.

Using the sequence formula;

a_{20} = 10 + (20 - 1)4.\\a_{20} = 10 + (19\times 4)\\a_{20}= 10 + 76\\a_{20}= 86.

Thus, the number of seats in row 20 was 86 seats.

Read more about Arithmetic Sequence at;

brainly.com/question/26960394

#SPJ1

3 0
2 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean \mu and standard deviation \sigma, we have these following probabilities

Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827

Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545

Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So \mu = 53, \sigma = 11

So:

Pr(53-11 \leq X \leq 53+11) = 0.6827

Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545

Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973

-----------

Pr(42 \leq X \leq 64) = 0.6827

Pr(31 \leq X \leq 75) = 0.9545

Pr(20 \leq X \leq 86) = 0.9973

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have Pr(31 \leq X \leq 75) = 0.9545 = 0.9545 subtracted by Pr(42 \leq X \leq 64) = 0.6827 is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

P = {0.9545 - 0.6827}{2} = 0.1359

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0
4 years ago
What is actively one pls pls pls i beg you
OLga [1]

Answer:

1. 9 to the power of 7

2. 7 to the power of 8

3. 10 to the power of 8.

4. 3 to the power of 9.

5. 2 to the power of 12.

Step-by-step explanation:

8 0
3 years ago
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