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snow_tiger [21]
3 years ago
9

Find the measure of x. (to the nearest tenth)

Mathematics
1 answer:
irga5000 [103]3 years ago
7 0

For the given triangle, x measures A) 25.7 units.

Step-by-step explanation:

Step 1:

In the given triangle, the angle is 56°. The adjacent side has a length of x units and the hypotenuse of the triangle measures 46 units.

To calculate the value of x, we determine the cos of the triangle where we divide the length of the adjacent side by the length of the hypotenuse.

cos\theta = \frac{adjacent side}{hypotenuse} .

Step 2:

The length of the adjacent side = x units.

The length of the hypotenuse = 46 units.

The angle of the triangle = 56°.

cos56 = \frac{x}{46}, cos 56 = 0.5591.

x =(0.5591)(46) = 25.7186.

So x = 25.7186 units, rounding this is off we get option A.

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The equation y = 5.50x represents the cost y (in dollars) for x visits to the
mr Goodwill [35]

In Graph x-axis represents number of visits and y-axis represents cost.

As graph comes up to be a linear one, so we can clearly say that cost is increasing linearly in multiples of 5.5 with increase in number of visits.

Example :

If museum is visited once then cost (y) = 5.5 x 1 = 5.5

If museum is visited twice then cost (y) = 5.5 x 2 = 11

If museum is visited thrice then cost (y) = 5.5 x 3 = 16.5

... cost (y) goes on in creasing when number of visits (x) increase with multiples of 5.5

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Find the number of real number solutions for the equation. x^2+5x+7=0
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In this case, we have

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Read 2 more answers
Based on a sample of 100 employees a 95% confidence interval is calculated for the mean age of all employees at a large firm. Th
babymother [125]

Answer:

a

\= x  =  40.85

b

E = 5.85

Ca  

   t_c =  2.08

Cb

   t_c  =   1.282

Explanation:

From the question we are told that

     The sample size is n  =  100

     The upper limit of the 95% confidence interval is  b =  47.2 years

     The lower limit of the 95% confidence interval is   a =  34.5 years

Generally the sample mean is mathematically represented as

         \= x  =  \frac{a + b }{2}

=>    \= x = \frac{47.2 + 34.5 }{2}

=>    \= x  =  40.85

Generally the margin of error is mathematically represented as

         E =  \frac{b- a }{ 2}

=>      E =  \frac{47.2- 34.5 }{ 2}

=>      E = 5.85

Considering question C a  

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

The  sample size is  n =  22

Given that the sample size is not sufficient enough i.e n < 30 we will make use of the student t distribution table  

Generally the degree of freedom is mathematically represented as

           df =  n- 1

=>        df =  22 - 1

=>        df =  21

Generally from the student  t  distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom  of  21 is  

   t_c =t_{\frac{\alpha }{2} ,  21  } =  2.08

Considering question C b

From the question we are told the confidence level is  80% , hence the level of significance is    

      \alpha = (100 - 80 ) \%

=>   \alpha = 0.20

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   t_c  =Z_{\frac{\alpha }{2} } =  1.282

4 0
3 years ago
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