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kirza4 [7]
3 years ago
8

The total cost f(x), in dollars, for renting a beach house for x days is shown: f(x) = 5 + 350x What does f(5) represent? The nu

mber of dollars it costs for 5 people to rent the beach house The number of dollars it costs to rent the beach house for 5 days The number of beach houses that can be rented for 5 days The number of days the beach house can be rented for a cost of $350
Mathematics
2 answers:
Sophie [7]3 years ago
5 0

Answer:

The number of dollars it costs to rent the beach house for 5 days

Step-by-step explanation:

if x is the number of days then f(5) is 5 days.

photoshop1234 [79]3 years ago
5 0

Answer:

The number of dollars it costs to rent the beach house for 5 days .

Step-by-step explanation:

f(x) = 5+350x. The enunciated says that f(x) is the cost in dollars for renting a house for x days, so f(5) is f(x) with x=5, that is, the cost in dollars for renting the house for 5 days. The exercise doesn't ask for the result but I am going to calculate it, there you can see it better.

f(5) = 5+350(5) = 5+1750 = 1755.

So, for 5 people, the cost in dollars for renting will be f(5)= 1755.

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Divide y by x, in this case 144 gets divided by 9, and you have your answer
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Suppose n people, n ≥ 3, play "odd person out" to decide who will buy the next round of refreshments. The n people each flip a f
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Answer:

Assume that all the coins involved here are fair coins.

a) Probability of finding the "odd" person in one round: \displaystyle n \cdot \left(\frac{1}{2}\right)^{n - 1}.

b) Probability of finding the "odd" person in the kth round: \displaystyle n \cdot \left(\frac{1}{2}\right)^{n - 1} \cdot \left( 1 - n \cdot \left(\frac{1}{2}\right)^{n - 1}\right)^{k - 1}.

c) Expected number of rounds: \displaystyle \frac{2^{n - 1}}{n}.

Step-by-step explanation:

<h3>a)</h3>

To decide the "odd" person, either of the following must happen:

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Assume that the coins here all are all fair. In other words, each has a 50\,\% chance of landing on the head and a

The binomial distribution can model the outcome of n coin-tosses. The chance of getting x heads out of

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<h3>b)</h3>

Since the coins here are all fair, the chance of determining the "odd" person would be \displaystyle n \cdot \left(\frac{1}{2}\right)^{n - 1} in all rounds.

When the chance p of getting a success in each round is the same, the geometric distribution would give the probability of getting the first success (that is, to find the "odd" person) in the kth round: (1 - p)^{k - 1} \cdot p. That's the same as the probability of getting one success after (k - 1) unsuccessful attempts.

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\displaystyle \underbrace{\left(1 - n \cdot \left(\frac{1}{2}\right)^{n - 1}\right)^{k - 1}}_{(1 - p)^{k - 1}} \cdot \underbrace{n \cdot \left(\frac{1}{2}\right)^{n - 1}}_{p}.

<h3>c)</h3>

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Answer:

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