QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer:
im going to have to go with V=2.14×10^{6}
Let’s solve this step by step. :)
First, let’s assign variables for the missing number: x and y.
so the 3 numbers would be x, y and 28
then we have 3 scenarios:
28 + x = 61
28 + y = 76
x + y = 81
Using the first equation, we can get x = 61-28 = 33
Using the 2nd equation, we can get y = 76-28 = 48
then, we can verify if our answer is right by substituting these values in the 3rd equation:
x + y = 81
33 + 48 = 81
81 = 81 ✔️
So the 3 numbers are 28, 33 and 48.
Answer:
-35.5
Step-by-step explanation:
Answer:
we know 147 degrees is G the x equals 37.7 degrees i tried sorry if this doesn't help