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labwork [276]
3 years ago
13

URGENT URGENT HELP NEEDED! I AM BEGGING...PLS SOLVE A GEOMETRY QUESTION. I HAVE ATTACHED THE SNIP. THANKS

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0
(x-h)^2+(y-k)^2=r^2\\
(h,k)-\text{ center}\\\\
x^2+y^2-6x+8y+21=0\\
x^2-6x+9+y^2+8y+16-4=0\\
(x-3)^2+(y+4)^2=4\\
\text{center}=(3,-4)\\
r=\sqrt4=2
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3 years ago
If AB = 8 and BC = 24, then AC =<br><br> If AB = 17 and AC = 68, then BC =
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(ii) Let suppose that AB and AC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:

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4 years ago
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