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3 years ago

URGENT URGENT HELP NEEDED! I AM BEGGING...PLS SOLVE A GEOMETRY QUESTION. I HAVE ATTACHED THE SNIP. THANKS

Mathematics

1 answer:

expeople1 [14]3 years ago

5 0

$(x-h)^2+(y-k)^2=r^2\\
(h,k)-\text{ center}\\\\
x^2+y^2-6x+8y+21=0\\
x^2-6x+9+y^2+8y+16-4=0\\
(x-3)^2+(y+4)^2=4\\
\text{center}=(3,-4)\\
r=\sqrt4=2$

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storchak [24]

Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)

You should already know this:

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You should also know this:

$sin^2(t) + cos^2(t) = 1\\\\\boxed{sin^2(t)} = 1 - cos^2(t)$

So plugging in both of those into our identity, we get:

$\frac{cos(t)}{sin(t)}\cdot sin^2(t) = cos(t)\cdot sin(t)$

Simplify the denominator on the LHS (Left Hand Side)

We get:

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2 years ago

Read 2 more answers

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Licemer1 [7]

Answer:

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2 years ago

Use the distributive property to express 40 in a different form.

Artemon [7]

Answer:

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Step-by-step explanation:

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2 years ago

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ruslelena [56]

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Every other choice has something either added to or subtracted from either x before it is squared or from the end.

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3 years ago