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Nataliya [291]
3 years ago
5

(6CQ) Evaluate the limit, or state that the limit does not exist. 2n+7n/13n

Mathematics
2 answers:
AysviL [449]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Fed [463]3 years ago
3 0

Answer:

option(b)

9/13

Step-by-step explanation:

Given the expression

\frac{2n+7n}{13n}

=\frac{9n}{13n}

n will cancel out on both sides

so,

9/13 will remain

As 9/13 is a constant so any value of n when approaches to a constant will not affect it. Hence limit = 9/13

<h3>It is one of the limit laws that</h3>

The limit of a constant function is equal to the constant.

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Of 60 randomly chosen students from a school surveyed,16 chose aquarium as their favorite fiel trip.There are 720 students in th
erik [133]

Answer:

192 students

Step-by-step explanation:

60 randomly students surveyed

16 chose aquarium as their favorite field trip.

720 students in total.

\frac{16}{60} = \frac{?}{720} =

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Analyze the diagram below and complete the instructions that follow.
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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
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