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Lubov Fominskaja [6]

3 years ago

12

If you vertically compress the absolute value parent function, f(x) = |x|, by a factor of 3, what is the equation of the new fun

ction? A. g(x) = |x – 3| B. g(x) = |x| C. g(x) = |3x| D. g(x) = 3|x|

1 answer:

iris [78.8K]3 years ago

6 0

The absolute value function would be D

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4 years ago

A particle moves along the x-axis so that at any time t, t ≥ 0, its acceleration is a(t) = -4sin(2t). If the velocity of the par

sasho [114]

The velocity of the particle is given by

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

Since $a(t)=-4\sin2t$ and $v(0)=7$ , we get

$\displaystyle\int_0^ta(u)\,\mathrm du=\int_0^t-4\sin2u\,\mathrm du=2\cos2u\bigg|_0^t=2\cos2t-2$

$\implies v(t)=2\cos2t+5$

Similarly, the position function is obtained via

$x(t)=x(0)+\displaystyle\int_0^tv(u)\,\mathrm du$

We know $v(t)$ and we're told that $x(0)=0$ , so

$\displaystyle\int_0^tv(u)\,\mathrm du=\int_0^t(2\cos2u+5)\,\mathrm du=\sin2u+5u\bigg|_0^t=\sin2t+5t$

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3 0

3 years ago

Write (1/3i)-(-6+2/3i) as a complex number in standard form

Eddi Din [679]

Answer:

$6+\frac{i}{3}$

Step-by-step explanation:

$\frac{1}{3\imath}-(-6+\frac{2}{3\imath})$

$\frac{1}{3\imath}+6-\frac{2}{3\imath}$

taking like terms together

$\frac{1}{3\imath}-\frac{2}{3\imath}+6$

taking LCM

$\frac{1-2}{3\imath}+6$

$\frac{-1}{3\imath}+6$

taking LCM

$\frac{-1+18\imath}{3\imath}$

splitting the term

$\frac{-1+18\imath}{3\imath}$

splitting the term

$-\frac{1}{3\imath}+\frac{18\imath}{3\imath}$

$-\frac{1\times3\imath}{3\imath \times \imath}+6$

$-\frac{i}{3\imath^2}+6$

we know that

$\imath^2=-1$

putting this value in above equation

$\frac{\imath}{3}+6$

7 0

3 years ago