Let g and b represent the numbers of grandstand and bleacher tickets sold.
.. g + b = 5716 . . . . . . . . . total number of tickets sold
.. 65g +40b = 341690 . . value of tickets sold
Using the first equation
.. g = 5716 -b
Sustituting into the second equation
.. 65(5716 -b) +40b = 341690
.. -25b + 371540 = 341690 . . . . . collect terms
.. -25b = -29850 . . . . . . . . . . . . . . subtract 371540
.. b = 1194 . . . . . . . . . . . . . . . . . . . . divide by -25
1194 bleacher tickets were sold.
Answer: He needs 9 hours to finish the task.
Step-by-step explanation:
Hi, first we have to subtract the gallons of water already in the tank (75) to the total capacity of the tank (300).
300-75 = 225
He needs to fill 225 gallons.
Since the pump Ross uses can fill 25 gallons of water per hour, the proportion is :
25 g / 1h
For 225 gallons:
225 g / x hours
Solving for x
25/1 = 225/x
x= 225/ (25/1)
x = 9 hours
Answer:
84
Step-by-step explanation:
The interquartile range is obtained using the relation :
Third quartile (Q3). - First quartile (Q1)
From. The boxplot :
Q3 = 96
Q1 = 12
Interquartile range (IQR) = Q3 - Q1 = 96 - 12 = 84
<h3>
Answer: Choice C</h3>
P = 11/40 + 1/4 - 1/20
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Explanation:
The formula we use is
P(A or B) = P(A) + P(B) - P(A and B)
In this case,
- P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
- P(B) = 20/80 = 1/4 = probability of picking someone taking French
- P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes
So,
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 11/40 + 1/4 - 1/20
which is why choice C is the answer
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Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.
