Answer:
i'm not too good in this, but i believe the answer is -3
Step-by-step explanation:
the hcf, highest common factor, of both -3 and -15 is -3, hence making the answer -3? if this is incorrect, i apologize.
Answer:
The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

The information provided is:
<em>x</em> = number of students who responded as"yes" = 70
<em>n</em> = sample size = 200
Confidence level = 95%
The formula to compute the sample proportion is:

The R codes for the construction of the 95% confidence interval is:
> x=70
> n=200
> p=x/n
> p
[1] 0.35
> s=sqrt((p*(1-p))/n)
> s
[1] 0.03372684
> E=qnorm(0.975)*s
> lower=p-E
> upper=p+E
> lower
[1] 0.2838966
> upper
[1] 0.4161034
Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).
15 - 5
14 - 5
13 - 5
12 - 5
11 - 5
10 - 5
9 - 5
8 - 5
7 - 5
6 - 5
5 - 5
I’m not sure if this was the answer you were looking for but I hoped it helped
<span>Perpendicular bisector is a<span> line which cuts a line segment into two equal parts at 90° </span>⇒
MN ⊥ BC
BM = CM</span>