Answer: have same slope or gradient.
Step-by-step explanation:
1 addition property of equality
Since there the -9 disappeared on the left and the +7 changed by 9 to a +16, 9 must have been added to both sides of the equation, and the addition property of equality states that the equation remains true when the same thing is added to both sides.
The statements are what?? Please post and I can help!!
Answer:
i) 
\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}
ii)
4^{3} + 8^{2} + \sqrt{9}
iii) ![(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}](https://tex.z-dn.net/?f=%28%5Cfrac%7B4%7D%7B5%7D%29%5E%7B2%7D.%20%5Csqrt%5B3%5D%7B8%7D%20%5Cleqx%5E%7B3%7D%20-%203x%20%2B%206%20%5Cleq%20%5Csqrt%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5CRightarrow%20%5Chspace%7B0.2cm%7D)
(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}
Step-by-step explanation:
i) \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}
ii) 4^{3} + 8^{2} + \sqrt{9}
iii) (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}
This statement is true :) please mark brainliest
