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allsm [11]
3 years ago
15

Angle ABC is congruent to angle CBD. Find x

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0
If the two given values are equal, we can just set them equal to each other and solve for the common variable.

In this case, we have 3x - 40 = 2x - 5

Add 40-2x to both sides of the equation: x = 35
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Shelly biked 21 miles in 4 hours. What is Shelly's average speed in miles per hour? At that same rate how many hours will it tak
Vedmedyk [2.9K]

So, we need to do the distance she travelled (21 miles) divided by the rate at which she travelled (4 hours). Therefore, because 21 divided by 4 is 5.25, she biked at a speed of 5.25 mph (Miles per hour). So, if she bikes 5.25 miles every hour we can divide 42 by 5.25 to get the time it would take her to travel 42 miles. Now, 42 divided by 5.25 equals 8, so that means for Shelly to bike 42 miles at her average speed of 5.25 mph, it would take her 8 hours.

5 0
3 years ago
Read 2 more answers
Evaluate x-(x-y3)); use x=9 and y=1
Ilya [14]

Answer:

-15

Step-by-step explanation:

9-(9-1*3)

9-8*3

9-24

-15

4 0
3 years ago
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Graph h(x) = 4x + 4 + 3.<br> Help me plz
saveliy_v [14]

Answer:

h(x)=4x+7

Step-by-step explanation:

4+3 can be added together if they do not have a variable. h(x)=4x+7. Plug in different x coordinates and solve for h(x). Now graph those points.

(-2,1)

(0,7)

(-1.75,0)

5 0
3 years ago
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Write algebraic expression<br> 17 less than the product of 3 and m
motikmotik
"17 less than" implies subtraction of the product of 3 and m, so the equation would be, if solving for x:
x=3m-17
4 0
4 years ago
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Use the given function and the given interval to complete parts a and b. f (x )f(x)equals=negative 2 x cubed plus 21 x squared m
Leya [2.2K]

Answer:

(A)The absolute maximum of f(x) is at x=5

Step-by-step explanation:

F(x)=−2x³+21x²−60x on [1,6]

Find the first derivative.

f'(x)=-6x²+42x-60

Set the first derivative equal to zero.

-6x²+42x-60=0

Solve to find the critical points.

x=2,5

Next, we use the endpoints and all critical points on the interval to test for any absolute extrema over the given interval.

x=1,2,5,6

This is done by evaluating the function at x=1,2,5,6.

F(1)=−2(1)³+21(1)²−60(1)=-41

F(2)=−2(2)³+21(2)²−60(2)=-52

F(5)=−2(5)³+21(5)²−60(5)=-25

F(6)=−2(6)³+21(6)²−60(6)=-36

The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.

Absolute Maximum: (5,-25)

Absolute Minimum: (2,-52)

The graph is attached.

The absolute minimum and maximum of f(x) are (2,-52) and (5,-25) respectively.

3 0
4 years ago
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