In geometry, the Segment Addition Postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB+BC= AC
The function is y=f(x)=-2x-3
the graph of this function are all pairs (x, y)=(x, f(x))=(x, -2x-3)
the y-intercept of a graph of a function, is the point where the graph cuts the y-axis, which happens at x=0.
at x=0, f(x)=f(0)=-2*0-3=-3
the x-intercept(s) of the graph, are the point(s) where the graph intersects the x-axis. At those points, the y-coordinate is 0.
so the x-intercept(s) are points of the form (x, 0)
now,
(x, 0)=(x, -2x-3)
0=-2x-3
2x=-3
x=-3/2
Answer:
x-intercept: (-3/2, 0)
y-intercept: (0, )
Answer:
about 1,620 cubic inches
Hope that was helpful.Thank you!
Answer:
Step-by-step explanation:
We can answer this in two ways: Differentiation and Graphing.
<u>Differentitate:</u>
The first derivative of a function yields a function that provides the slope for any point on the line of the original function. The slope of a vertex is zero, so we can set the first derivative to 0 and solve for x.
f(x) = 3(x-1)^2 + 4
f(x) = 3(x-1)(x-1) + 4
f(x) = 3(x^2 - 2x + 1) + 4
f(x) = 3x^2 - 6x + 7
f'(x) = 6x -6
Set this = 0 and find x:
0 = 6x -6
x = 1
The value of y when x=1 in the original equation is:
f(1) = 3(1-1)^2 + 4
y = 4
The vertex is (1,4)
<u>Graph:</u>
You can use DESMOS to plot the function. The result is attached. Look for the vertex and read the coordinates. (1,4) seems to work.