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zysi [14]
3 years ago
6

Evaluate \dfrac13m-1-\dfrac12n

Mathematics
1 answer:
romanna [79]3 years ago
7 0

Answer:

The expression is equal to zero for the given values

Step-by-step explanation:

<u><em>The correct question is</em></u>

Evaluate start fraction, 1, divided by, 3, end fraction, m, minus, 1, minus, start fraction, 1, divided by, 2, end fraction, n   when m=21 and n=12

we have the expression

 \frac{1}{3}m-1-\frac{1}{2}n

we know that

To evaluate the expression substitute the given values of m and n

For m=21 and n=12

\frac{1}{3}(21)-1-\frac{1}{2}(12)

solve the multiplications

7-1-6

solve the subtraction

7-7\\0

therefore

The expression is equal to zero for the given values

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Akimi4 [234]

Answer:

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Step-by-step explanation:

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A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0
4 years ago
What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)
PIT_PIT [208]

9514 1404 393

Answer:

  • common denominator: (x² -4)
  • simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

  a² -b² = (a -b)(a +b)

__

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

  \dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}

3 0
3 years ago
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Andrews [41]

Answer:

No,It will be a negative answer.

Step-by-step explanation:

We can see that there are 3 negative numbers.

2 negatives numbers multiplied makes a positive number.

The remaining negative number will make the answer a negative number.

7 0
3 years ago
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