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NeX [460]
2 years ago
6

Which equation could represent a linear combination of the system?

Mathematics
1 answer:
Ghella [55]2 years ago
7 0

The equation that could represent a linear combination of the system 2/3x + 5/2y = 15 and 4x + 15y = 12 is 0 = 26

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change, slope or gradient

<h3>How to determine the linear combination to the system?</h3>

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2/3x + 5/2y = 15

4x + 15y = 12

Multiply the first equation by 6, to eliminate the fractions.

6 * (2/3x + 5/2y = 15)

This gives

4x + 15y = 90

Subtract the equation 4x + 15y = 90 from 4x + 15y = 12

4x - 4x + 15y - 15y = 12 - 90

Evaluate the difference

0 + 0 = -78

Evaluate the sum

0 = -78

The above equation is the same equation as option (b) 0 = 26

This is so because they both represent that the system of equations have no solution

Hence, the equation that could represent a linear combination of the system is 0 = 26

Read more about system of linear equations at

brainly.com/question/14323743

#SPJ1

<u>Complete question</u>

The system of equations below has no solution.

2/3x + 5/2y = 15

4x + 15y = 12

Which equation could represent a linear combination of the system?

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Answer:

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Step-by-step explanation:

The surface area of a sphere can be found using the formula A=4\pi r^2. Since the radius is 13 units, substitute r=13.

SA=4\pi r^2\\SA = 4 \pi (13)^2\\SA = 4 \pi *169\\SA = 2122.64

Without multiplying 3.14 for \pi, the answer is

SA = 169*4 \ pi\\SA = 676 \pi

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3 years ago
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Answer:

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Step-by-step explanation:

5*2=10

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What is 2.1x10 to the 3rd power in standard form?
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3 years ago
What is the equation of a circle with its center at (0,-2) and passing through the point (3,-5)
Ksivusya [100]
Circle's Standard Form Equation:
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First you need to substitute the C (0,-2) in the equation, where: Xo = 0 and Yo = -2;

r^{2} = (x - 0)^{2} + (y - ( -2))^{2} \\ r^{2} = x^{2} + (y + 2)^{2}

Now you substitute the Point (3,-5) values in the last expression, where: X = 3 and Y = -5;

r^{2} = 3^{2} + (( - 5) + 2)^{2} \\ r ^{2} = 9 + ( - 3)^{2} \\ r^{2} = 9 + 9 \\ {r}^{2} = 18

Now you get the R^2 value and substitute in the equation that you found putting the C values on it:

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Here is your standard form equation of the circle.
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3 years ago
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