4x + 2y + z = 8 solve for x, y, and z

1 answer:

5 0

Hello there. I did one part of your question.

4x + 2y + z = 8

−4x−2y+8

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------------------------------------------------------------------
Equation
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x² + 4x = 0

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Add a constant
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x² + 4x + (4/2)² - (4/2)² = 0 ← Add 2² to form perfect square

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Evaluate bracket
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x² + 4x + 2² - 2² = 0

------------------------------------------------------------------
Form the perfect square
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(x + 2)² = 4

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Square root both sides
------------------------------------------------------------------
(x+2) = $\pm$ √4

------------------------------------------------------------------
Evaluate the square root
------------------------------------------------------------------
(x+2) = $\pm$ 2

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Solve x
------------------------------------------------------------------
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------------------------------------------------------------------
Answer: The constant to add is 4 and the value of x = 0 or -4
------------------------------------------------------------------

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