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2 years ago

How do you find the probability of the sum of 6 when rolling a die?

Mathematics

1 answer:

alexdok [17]2 years ago

6 0

there is a 1 to 5 probablilty that you will roll the sum of 6 with two dice.

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you must take medicine in 4 equal doses each day. each days medicine come in a single container and measure 3 1/5 tablespoons. h

erastova [34]

1.2 tablespoons in each dose

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2 years ago

There are two friends. Each friend has a dollar to buy some pie. The first friend buys two-eighths of a pie for a dollar. The se

Firlakuza [10]

Answer:

Neither they get the same amount

Step-by-step explanation:

7 0

3 years ago

Simplify the expression 10-4x(6+5-1) divided by 8+7

Eddi Din [679]

Simple,

writing out the problem...

$\frac{10-4x(6+5-1)}{15}$

Simplify it...

-4x(6+5-1)

-4x(11-1)

-4x(10)

-40x

Making it look like...

$\frac{10-40x}{15}$

Cancel out the common factors...

Thus making the answer:

$- \frac{2(4x-1)}{3}$ .

8 0

2 years ago

Simplify:(y²+z²) -2yz

VMariaS [17]

Answer:

$(y-z)^{2}$

Step-by-step explanation:

$(y^{2}+z^{2} ) -2yz\\\\y^{2} +z^{2} - 2yz\\\\y^{2} +2yz + z^{2}\\\\(y-z)^2\\$

5 0

3 years ago

PLS HELP ME!!! which matrix represents the system of equations below {8x-9y+13z=11

Finger [1]

Answer:

The answer is below

Step-by-step explanation:

The system of equations:

8x-9y+13z=11

-8x-5y+5z=15

3x+4y-8z=-10

The equations can be represented in matrix form as:

AX = B

X = A⁻¹B

Therefore:

$\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] ^{-1}\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\$

$\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}\frac{1}{19} &-\frac{1}{19}&\frac{1}{19}\\-\frac{49}{380}&-\frac{103}{380}&-\frac{36}{95} \\-\frac{17}{380}&-\frac{69}{380}&-\frac{28}{95} \end{array}\right] \left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}-0.74\\-1.69\\0.13\end{array}\right] \\$

4 0

2 years ago