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3 years ago

Could I have help to find x?

Mathematics

2 answers:

-BARSIC- [3]3 years ago

7 0

$\cfrac{16^{x+1}}{8^{2x+2}}=16 \\ \\ \cfrac{(2^4)^{x+1}}{(2^3)^{2x+2}}=2^4 \\ \\ \cfrac{2^{4x+4}}{2^{6x+6}}=2^4 \\ \\ 2^{4x+4-(6x+6)}=2^4 \\ 2^{4x+4-6x-6}=2^4 \\ 2^{-2x-2}=2^4\\ \\ -2x-2=4 \\ -2x = 4+2 \\ -2x=6 \\ 2x=-6 \\ x=-6/2 \\ x=-3$

Andreas93 [3]3 years ago

6 0

$\dfrac{16^{x+1}}{8^{2x+2}}=16\\
\dfrac{2^{4x+4}}{2^{6x+6}}=2^4\\
2^{4x+4-6x-6}=2^4\\
2^{-2x-2}=2^4\\
-2x-2=4\\
-2x=6\\
x=-3
$

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