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Crazy boy [7]
3 years ago
9

Could I have help to find x?

Mathematics
2 answers:
-BARSIC- [3]3 years ago
7 0
\cfrac{16^{x+1}}{8^{2x+2}}=16 \\ \\  \cfrac{(2^4)^{x+1}}{(2^3)^{2x+2}}=2^4  \\  \\  \cfrac{2^{4x+4}}{2^{6x+6}}=2^4 \\ \\ 2^{4x+4-(6x+6)}=2^4 \\ 2^{4x+4-6x-6}=2^4  \\ 2^{-2x-2}=2^4\\  \\ -2x-2=4 \\ -2x = 4+2 \\ -2x=6 \\ 2x=-6 \\ x=-6/2 \\ x=-3
Andreas93 [3]3 years ago
6 0
\dfrac{16^{x+1}}{8^{2x+2}}=16\\
\dfrac{2^{4x+4}}{2^{6x+6}}=2^4\\
2^{4x+4-6x-6}=2^4\\
2^{-2x-2}=2^4\\
-2x-2=4\\
-2x=6\\
x=-3

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How many computers must the AB Computer Company sell to break even? Let x be the number of computers.
Eduardwww [97]

Answer:

The Company AB must sell 116 computers to break even

Step-by-step explanation:

we have

R(x)=1.5x -----> equation A

C(x)=145+\frac{1}{4}x ----> equation B

where

C is the cost function

R is the revenue function

x is the number of computers sold

we know that

Break even is when the cost is equal to the revenue

so

equate equation A and equation B

1.5x=145+\frac{1}{4}x

Solve for x

subtract 1/4x both sides

1.5x-\frac{1}{4}x=145

1.5x-0.25x=145

1.25x=145

Divide by 1.25 both sides

x=116

therefore

The Company AB must sell 116 computers to break even

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OLEGan [10]
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Is 5.67 A)rational B)Irrational C)whole D) natural E)integer
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ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of (f \circ g)(x) = f(g(x)) is the same as the domain of g(x)

The domain for g(x) is \{x|x \ne 13\} saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0
3 years ago
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