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Blizzard [7]
2 years ago
8

Someone help please I couldn't answer this on the test

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
5 0
A is continuous
B is discrete
C is not a function
S is a function
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If the car spends 2.5 hours going 35 miles per hour on the trip, how long does it spend going 35 miles per hours
Neporo4naja [7]

its spends 2.5 hours going 35 miles per hour. so the answer is 2.5 because 35 miles as you said goes 2.5 hours

6 0
3 years ago
haha 6 days of history, 3 weeks of math, and 1 week of english all to do tn. It's currently 9:27. oh well who cares aha kinda fu
Mashcka [7]

Answer:

oop... glll

Step-by-step explanation:

have u uploaded any? Maybe I can help

4 0
2 years ago
Read 2 more answers
In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

8 0
3 years ago
Read 2 more answers
Assessment timer and count Assessment items A hockey league has a total of 252 players on 12 teams. How many players per team ar
sammy [17]
There are 21 people on each team. First you can divide 252 and 12. You get 21. To check you can then multiply 12 and 21 and get 252
3 0
3 years ago
Read 2 more answers
Semicircles
Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is 9.1\ cm^2

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

A=b^2

where

b is the length side of the square

we have

b=4\ cm

substitute

A=4^2=16\ cm^2

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

A=\pi r^{2}

The diameter of the circle is equal to the length side of the square

so

r=\frac{b}{2}=\frac{4}{2}=2\ cm ---> radius is half the diameter

substitute

A=\pi (2)^{2}

A=4\pi\ cm^2

Therefore, the area of 2 "not-shaded" regions is:

A=(16-4\pi) \ cm^2

and the area of 4 "not-shaded" regions is:

A=2(16-4\pi)=(32-8\pi)\ cm^2

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

so

A=16-(32-8\pi)=(8\pi-16)\ cm^2  

---> exact value

assume

\pi =3.14

substitute

A=(8(3.14)-16)=9.1\ cm^2

8 0
3 years ago
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