f(x) = 5x − 1 and g(x) = 2x^2 + 1
(f × g)(x) = (5x − 1)(2x^2 + 1)
(f × g)(x) = 10x^3 - 2x^2 + 5x - 1
Substitute x = - 3
(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1
(f × g)(-3) = 10(-27) - 2(9) -15 - 1
(f × g)(-3) =-270 - 18 - 16
(f × g)(-3) = -236
Answer
- 236
So it would be 3s + 7s + 11s + 15s + 19s + 23s + 27s. Hope this helps
Answer:
56 degrees.
Step-by-step explanation:
We need the measure of < g.
The triangle formed by the 2 tangents and the chord is isosceles, because 2 tangents from a point outside a circle are of equal length (by the Two Tangents theorem).
Also one of the base angles are equal to 62 degrees ( by The Tangent Chord theorem). In fact both base angles are 62 degrees because the triangles an isosceles.
So measure of angle g = 180 - 2(62)
= 56 degrees.
Step-by-step explanation:
T = time in seconds
H = distance
Tground = time to return to ground
Tmax = time at maximum height
H = -16T^2 + 672T...eqn 1
projectile returns to ground at H =0,
subs for H in eqn 1...
0 = -16T^2 + 672T
solving for T we get...
16T^2 = 672T
=> Tground = 42secs
Tmax = 0.5 Tground = 21secs
