Answer:
not equivalent
Step-by-step explanation:
solve for x
4-5x=24
-5x=20
x = - 4
5x=20
x = 4
no they are not equivalent
Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
7x - y= -5. Standard form is when it is written with x and y on the same side, but x is not negative or a fraction. To find the slope and y intercept, you must change the first two equations to slope intercept. You get y=7x-5 for the first one and y=11/3x+5 for the seccond equation. Take the 5 as your y intercept and the 7 as your slope and you get y=7x+5. Now you need to change it into standard form. When all is said and done, your final answer should be 7x - y = -5.
