Question

A right rectangular prism has a length of 5 cm, a width of 4 cm, and a height of 3 cm. The dimensions of the prism are doubled. What is the surface area of the enlarged prism?

Answer 1

Answer:

376 square centimeters

Step-by-step explanation:

When doubled, the new length is 5*2=10 cm, new width is 4*2=8 cm, and new height is 3*2=6 cm.

The surface area of a rectangular prism is given by : $2(lw+wh+lh)$

Where l is length, w is width, and h is height

Plugging in the new values we get:

$2(lw+wh+lh)\\=2((10)(8)+(8)(6)+(10)(6))\\=2(80+48+60)\\=2(188)\\=376$

The surface area of the enlarged prism = 376 cm^2

Answer 2

Answer: 376 cm²

Step-by-step explanation:

If the dimensions are doubled then:

length=10cm

width=8cm

height=6cm

You must apply the formula for calculate the surface area of a rectangular prism, whih is shown below:

$SA=2(wl+lh+hw)$

Where l is the length, w is the width and h is the height.

WHen you substitute values, you obtain the following result:

$SA=2[(8cm*10cm)+(10cm)(6cm)+(6cm)(8cm)]$

$SA=376cm^2$