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Artemon [7]
4 years ago
13

Please hellppp ......​

Mathematics
2 answers:
andrezito [222]4 years ago
8 0

Answer:

\boxed{BC = 11.9 \ cm}

Step-by-step explanation:

Sin A = \frac{opposite}{hypotenuse}

Where A = 58°, Opposite = BC and AC = 14 cm

Sin 58 = \frac{BC}{14}

BC = 0.848 * 14

BC = 11.9 cm

katovenus [111]4 years ago
7 0

Answer:

<h2>BC = 11.9</h2>

Step-by-step explanation:

To solve for BC we use sine

sin ∅ = opposite / hypotenuse

From the question

AC is the hypotenuse

BC is the opposite

So we have

sin 58 = BC / AC

sin 58 = BC / 14

BC = 14 sin 58

BC = 11.87

BC = 11.9 to one decimal place

Hope this helps you

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Enter the ordered pair for the vertices for (Ry-axis ○ T(2, 0))(QRST).
zhannawk [14.2K]

Answer:

The answer is:

Q' = (-3, 3)\\\\R' = (-5, -3)\\\\S' = (-2, -2)\\\\T' = (0, 1)\\\\

Step-by-step explanation:

All vertices of its quadrilateral were co-ordinated;  

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T(2, 0) \ QRST \to  T(-2 + 2, 1), \ Q(1 + 2, 3), \ S(0 + 2, -2), \ R(3 + 2, -3)

T(2, 0) \ QRST\to  T(0, 1), \ Q(3, 3), \ S(2, -2), \ R(5, -3)

A preimage (x, y) will be the image in the next phase R-y-axis reflecting mostly on the y-axis (-x, y)  and we've got it;  

R y-axis (T(0, 1), \ Q(3, 3), \ S(2, -2), \ R(5, -3)) = \ T'(0, 1), \ Q'(-3, 3), \ S'(-2, -2), \ R'(-5, -3)From which we get (Ry-axis \ T(2, 0)) \ (QRST =  T'(0, 1), \  Q'(-3, 3), \ S'(-2, -2),\  R'(-5,-3).

7 0
3 years ago
What is the solution to the following system of linear equations<br> x + y = -8<br> 3x = -4 + y
storchak [24]

Answer:

the answer is 4x a

Step-by-step explanation:

hope it helps

4 0
2 years ago
Cammi needs 36 postcards . She buys 4 packages of 10 postcards . How many postcards will cammi have left over? explain
Nonamiya [84]

Answer:

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Step-by-step explanation:

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hope this helps :)

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The solution is r= 7/a-x How did i do this?
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