3x = -5y -------------- (1)
6x - 7y = 17 --------- (2)
From (1):
3x = -5y
x = -5/3 y ---------- sub into (2)
6 (-5/3 y) - 7y = 17
-10y - 7y = 17
-17y = 17
y = -1 ------------ Sub into (1)
3x = -5 (-1)
3x = 5
x = 5/3
Ans: x = 5/3, y = -1
Answer:
no mode
Step-by-step explanation:
Mode is the most common number shown therefore....
since there are no numbers repeated, the answer is no mode
Hey there! I'm happy to help!
Let's convert the decimals to fraction form.
0.5=5/10=1/2
-1/7
-0.2= -2/10= -1/5
1/3
We know that the bigger the number in the denominator, the smaller the fraction is if the numerators are all the same.
First off, we have the negative numbers which are smaller than the other numbers. We have -1/7 and -1/5. We know that the 1/5 is a bigger fraction, but it is negatively bigger, so that is going to be the lesser number.
-1/5, -1/7
And with our bigger ones, we have 1/3 and 1/2. 1/2 is the bigger number here, so that will be the last one. Let's also be sure to convert back to our original forms! Here is our order :
-0.2, -1/7, 1/3, 0.5
Have a wonderful day and keep on learning! :D
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
