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r-ruslan [8.4K]
3 years ago
8

Find the number such that when it is added to 5 and the sum is divided by 3 the result is the same as one twelve in divided by x

Mathematics
1 answer:
Oksana_A [137]3 years ago
8 0

Answer:

0.05 or -5.05

Step-by-step explanation:

Let the number be x

Then

(X+5)/3=(1/12)÷X

Cross multiplication

It will be;

12x²+60x=3

By general equation,

X=0.05 or -5.05

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2 years ago
4x + 3y = 16<br> 7x+6y=31<br> O A. (1,3)<br> B. (1.4)<br> C. (4,0)<br> OD. (4,3)<br> SUBMIT
klasskru [66]

Answer:

B

Step-by-step explanation:

Given the 2 equations

4x + 3y = 16 → (1)

7x + 6y = 31 → (2)

Multiplying (1) by - 2 and adding to (2) will eliminate the term in y

- 8x - 6y = - 32 → (3)

Add (2) and (3) term by term

- x = - 1 ( multiply both sides by - 1 )

x = 1

Substitute x = 1 in either of the 2 equations and solve for y

Substituting in (1)

4(1) + 3y = 16

4 + 3y = 16 ( subtract 4 from both sides )

3y = 12 ( divide both sides by 3 )

y = 4

Solution is (1, 4 ) → B

4 0
3 years ago
Chandra said she could paint 7 out of 20 toys for the toy drive. Tuesday, she painted 4. What percent of the 20 toys does she st
vredina [299]

Answer:

80%

Step-by-step explanation:

out of 20, 1 would be 5%  

4 = 20%

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6 0
2 years ago
!!!!PLEASE HELP!!!
Wittaler [7]

Answer:

C. x = -1 ; x ~8.1

Step-by-step explanation:

First we graph f(x)= -\sqrt{x+2} -3

Here we have x+2 under the square root. x+2>=0, x>=-2

So we take some x  values greater than -2  and find out f(x)  to make a table for graphing

x        f(x)

-2       -\sqrt{-2+2} -3=-3

-1        -4

2        -5

Graph it  and extent the graph

Now we graph g(x)= -2|x-3| + 4

Given equation is in the form of g(x) = a|x-h| + k

where (h,k) is the vertex

here h= 3  and k = 4, so vertex is (3,4)

Now make a table, pick some numbers for x  less than and greater than vertex

x     y

-1     -2|-1-3| + 4=-4

0    -2|0-3| + 4=-2

3    4

6     -2

Both graphs are attached below

The graph of f(x)  and g(x) interests  at x= -1  and x=8.1

3 0
3 years ago
Read 2 more answers
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