Find the number such that when it is added to 5 and the sum is divided by 3 the result is the same as one twelve in divided by x
1 answer:
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Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
P = 24 + 4.47 = 28.47
D) 28.472
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
P = 24 + 4.47 = 28.47
D) 28.472