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lubasha [3.4K]
3 years ago
13

Write down 4 odd digit numbers that will add up to 19

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0
<h2>There is no 4 odd digits that will add up to 19.</h2>
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ValentinkaMS [17]
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Multiple choice help please
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A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i what is the students mistakes
Rufina [12.5K]

Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

2. The student has only multiplied the real parts and the imaginary parts.

Correct value =22+7i.

Step-by-step explanation:

The given expression is

(4+5i)(3-2i)

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

(4+5i)(3-2i)=4\times 3+5\times (-2)i=12-10i

Which is not correct. The correct steps are shown below.

Using distributive property, we get

4(3-2i)+5i(3-2i)

4(3)+4(-2i)+5i(3)+5i(-2i)

12-8i+15i-10i^2

12+7i-10(-1)       [\because i^2=-1]

12+7i+10

22+7i

Therefore, the correct value of (4+5i)(3-2i) is 22+7i.

4 0
3 years ago
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Answer:

2 is not a solution

Step-by-step explanation:

x < -12

<u>Step 1:  Check if 2 is less than -12</u>

2 < -12

No, this doesn't work

Answer:  2 is not a solution

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Answer:

Your Answer would be C: $37.95

Step-by-step explanation:

Take 3.45 Multiply by 11 And get your answer

6 0
3 years ago
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