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netineya [11]
3 years ago
14

What is the distance between?

Mathematics
1 answer:
kykrilka [37]3 years ago
3 0
Answer: 3 1/2 units

Since the y values are the same, count from -2 1/2 value to 1 on the x-axes which would give you positive 3 1/2
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The slope of the line that contains the points (2, 11) and (0, 5 ) is 3. Which of the following equations represents this line?
taurus [48]

Answer:

C

Step-by-step explanation:

This is your current equation: y= 3x + b. Next, plug in one of your coordinates to the equation. It doesn't matter which one. I'm going to use the second ordered pair, so it should look like this: 5 = 3(0) + b. Multiply 3 and 0 to get 5 = b. So, your equation is y = 3x + 5. The correct answer is C. Hope this helped!

7 0
3 years ago
Given that points A, B, and C are the midpoints of their respective sides, which of the following is true about the figure?
mamaluj [8]

Answer: A

Step-by-step explanation:n

4 0
3 years ago
Answer quick please,
lbvjy [14]

Answer:

132 minutes

Step-by-step explanation:

1 Km = (60)(8)+15=495 seconds

4 mornings = (495)(4) =1980 seconds

4 weeks = (1980)(4) = 7920 sec.

7920/60 = 132 minutes

4 0
2 years ago
How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid​ solution?
horsena [70]
Work in  amount of pure acid   let x = gallons of pure acid required.
then we have the equation:-

x + 55(0.6) = 0.80(x + 55)

x + 33 = 0.80x + 44
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4 0
3 years ago
Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x
egoroff_w [7]

Answer:

y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

<u>Determine the slope (</u><em><u>m</u></em><u>):</u>

y = 1 -2x

Rearrange into slope-intercept form:

y = -2x+1

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of \displaystyle\frac{1}{2}. Plug this into y=mx+b:

y=\displaystyle\frac{1}{2} x+b

<u>Determine the y-intercept (</u><em><u>b</u></em><u>):</u>

y=\displaystyle\frac{1}{2} x+b

Plug in the given point (1,3) and solve for <em>b</em>:

3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}

Therefore, the y-intercept is \displaystyle \frac{5}{2}. Plug this back into y=\displaystyle\frac{1}{2} x+b:

y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}

I hope this helps!

8 0
2 years ago
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