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prohojiy [21]
2 years ago
14

t%7B2%7D%20%2B%20%20%5Csqrt%7B3%7D%20%20%7D%20%20%2B%20...%20%2B%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7Bn%20%2B%201%7D%20%20%2B%20%20%5Csqrt%7Bn%7D%20%7D%20%20%20%5Cleqslant%2020" id="TexFormula1" title=" \frac{1}{ \sqrt{2} + 1 } + \frac{1}{ \sqrt{2} + \sqrt{3} } + ... + \frac{1}{ \sqrt{n + 1} + \sqrt{n} } \leqslant 20" alt=" \frac{1}{ \sqrt{2} + 1 } + \frac{1}{ \sqrt{2} + \sqrt{3} } + ... + \frac{1}{ \sqrt{n + 1} + \sqrt{n} } \leqslant 20" align="absmiddle" class="latex-formula">
help....................​
Mathematics
1 answer:
statuscvo [17]2 years ago
8 0

Answer:

all i see is ..........

Step-by-step explanation:

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Students in miss moseley's fourth grade class
Tpy6a [65]

Answer:

what?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If you add 12 to my number and then multiply the result by 3, you will get 64 more than two-thirds of my number. Find my number.
anastassius [24]

Answer:

The number is 12

Step-by-step explanation:

[] First, let's turn all these words into something mathematical. N will equal "my number"

-><u> If you add 12 to my number</u> and then multiply the result by 3, you will get 64 more than two-thirds of my number.

-> n + 12 <u>and then multiply the result by 3</u>, you will get 64 more than two-thirds of my number.

-> 3(n + 12), you will get 64 more than <u>two-thirds of my number</u>.

-> 3(n + 12) = <u>64 more than</u> \frac{2n}{3}

-> 3(n + 12) = 64 +  \frac{2n}{3}

[] Phew, okay. Now it is something we can solve and less scary;

[Given]

3(n + 12) = 64 +  \frac{2n}{3}

[Distribute]

3n + 36 = 64 +  \frac{2n}{3}

[Multiply both sides by 3]

9n + 108 = 192 + 2n

[Subtract 108 and 2n from both sides]

7n = 84

[Divide both sides by 4]

n = 12

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0
3 years ago
Can someone help me please ? Thanks!
notka56 [123]
Use pythagorean theorem for all of them
a. 3, 4, 5
3^2+4^2?5^2
9+16?25
25=25
right 

b. 5, 6, 7
5^2+6^2=7^2
25+36=49
61>49
acute

c. 64+81=144
145>144
acute

hope this helps!
6 0
3 years ago
Read 2 more answers
Help please. Solve the system of equations using substitution. Show your work in the workspace provided below.
LenKa [72]

Answer:

x=0 y=-11 (0,-11)

Step-by-step explanation:

1. take what y equals (3x-11) and plug it in for y in the second equation

Should look like this: O= 6x-2(3x-11)-22

2. Then distribute O=6x-6x+22-22

3. Then combine like terms O= 0 the 22's cancel out as well as the x's

x= 0

4. plug 0 in for x in the first equation y=3(0)-11

5. y= -11

6. x=0 y=-11 (0,-11)

6 0
3 years ago
The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater
Sergio039 [100]

Answer:

A.) Function 1 has the larger maximum at (4, 1).

Step-by-step explanation:

No step-by-step explanation, nobody pays attention to them anyway.

3 0
3 years ago
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