This is a right angle triangle problem
drawing a vertical line at from the point where the ramp touches the car park leaves a right angle triangle with the
opposite being 2m
hypothenus being 10m
adjacent unknown
we could use sine
SineO equal to opposite over hypothenus
SineO equal to 2/10
SineO equal to 0.2
O equal to Sine^1(0.2)
O equal to 11 .5
The angle between the ramp and the horizontal is 11.5 degrees
You can divide a triangle using medians. Let's name triangle ΔABC shown in figure 1. So you must start at one of the vertices and then bisect the opposite side. Let's start with the point A and then we bisect the opposite side. Then the length from B to D is equal to the length from D to C. So let's take the point B and then we bisect the opposite side. Then the length from A to E is equal to the length from E to C. The same reasoning happens with the point C. So we have, in figure 2, the triangle ΔABC divided into six triangles which all have the same area.
Answer:
45
Step-by-step explanation:
n/15=30
therefore n=450
hence n/10 = 45
It's not c so it mite be eather b or a I would say its b