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3 years ago

PLZZ HELPP FIRST ANSWER THATS CORRECT GETS BRAINLIEST

1 answer:

5 0

Alright, so the sum of two days is going to equal zero.
The variable here is what Jesse got on the first day. Let's call it "x".
x-6=0
x is the first day's score, -6 is the second day's score, and the total score is zero.
Now, add 6 to both sides.
x-6=0
+6 +6
x=6
Jesse's score for the first day was (+)6.

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What is ratio 54 1:16:2

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3 years ago

Solve the proportions using cross products. Round to the nearest hundredth is necessary. 21miles/49hours = 15miles h hours

SSSSS [86.1K]

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4 years ago

What the function?<br> y = 2.5x + 8

garik1379 [7]

Answer:

Step-by-step explanation:

This is a linear function with y-intercept (0, 8) and slope 2.5.

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3 years ago

Michael Beasley is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next

Elodia [21]

Answer: C. $0.75^4$

Step-by-step explanation:

Let x be the binomial variable that denotes the number of makes.

Since each throw is independent from the other throw , so we can say it follows Binomial distribution .

So $X\sim Bin(n=4 , p=0.75)$

Binomial distribution formula: The probability of getting x success in n trials :

$P(X=x)=^nC_xp^n(1-p)^{n-x}$ , where p = probability of getting success in each trial.

Then, the probability of Michael Beasley making all of his next 4 free throw attempts will be :

$P(X=4)=^4C_4(0.75)^4(1-0.75)^{0}$

$=(1)(0.75)^4(1)\ \ [\because\ ^nC_n=1]\\\\=(0.75)^4$

Thus, the probability of Michael Beasley making all of his next 4 free throw attempts is $=0.75^4$

Hence, the correct answer is C. $0.75^4$ .

4 0

3 years ago

The useful life of a certain piece of equipment is determined by the following formula: u=(8d)/h^2, where u is the useful life o

Anni [7]

Answer:

The correct answer is E.

Step-by-step explanation:

First I look for the relationships between the coefficients. The first term corresponds to the base value.

$\frac{8*d}{h^{2}} = \frac{8}{1} * \frac{d}{h^{2} }$

The second term corresponds to the value obtained when the density of the underlying material is doubled and the daily usage of the equipment is halved.

$\frac{2*8*d}{(0,5*h)^{2}} = \frac{16*d}{0,25 * h^{2}} = \frac{16}{0,25} * \frac{d}{h^{2} }$

With the I get the ratio of coefficients of $\frac{d}{h^{2}}$ :

$\frac{8}{1}$ = 8

$\frac{16}{0,25}$ = 64

Now I calculate the percentage increase in the useful life of the equipment as:

% = $\frac{64}{8}$ * %100 = %800

3 0

4 years ago