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katrin2010 [14]
3 years ago
15

PLZZ HELPP FIRST ANSWER THATS CORRECT GETS BRAINLIEST

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0
Alright, so the sum of two days is going to equal zero.
The variable here is what Jesse got on the first day. Let's call it "x".
x-6=0
x is the first day's score, -6 is the second day's score, and the total score is zero.
Now, add 6 to both sides.
x-6=0
+6   +6
x=6
Jesse's score for the first day was (+)6.
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What percent of a dozen is 3
Margaret [11]

Answer:

25%

Step-by-step explanation:

Percentages are one of several ways of describing quantities' relationships to one another. Specifying one number as a percentage of another means specifying the fraction of the second quantity the first comprises. The percentage value is the number that, divided by 100, equals that fraction. To express the percentage as a whole number, round it accordingly. Some applications, however, don't require percentages as exact whole figures.

Divide the first number the second. For instance, if you want to find what percentage 43 is out of 57, divide 43 by 57 to get 0.754386.

6 0
3 years ago
PLEASE HELP !!! Will give brainest !!!!!​
Margarita [4]

Answer:

9.6

2.4.

Step-by-step explanation:

It is easy. If you do with calculator it's easy.

8 0
2 years ago
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Number 12 AND QUICKKKK
deff fn [24]

Answer:

id say A

because its an opened circle, and when its opened its usually not with the little dash and there's no negative number (that i know of)

3 0
2 years ago
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Maggie purchased 8 pounds of ground beef for $18.00. Which of the following does NOT represent the same price per pound?
agasfer [191]

Answer: 5 pounds of ground beef ( don't see second :-( )

Step-by-step explanation: I found the unit rate per pound ( 2.25 ) and then multiplied that by the other pounds to compare the two prices and I only found 5 pounds to be incorrect, but I'll keep digging, hope this helps!

7 0
3 years ago
Which of the following expression is equal to x^2+25?
nignag [31]
A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2


B: (x - 5i)^2
= (x  +   - 5i)(x +  - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2


C: (x - 5i)(x + 5i)
= (x +  - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2


D: (x + 10i)(x  - 15i)
= (x + 10i)(x +  - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
=  - 150i^2 + 5ix + x^2



Hope that helps!!!

6 0
3 years ago
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