<span>∵ There is a proportional relationship between the mass and the volume of the places of metal.
Let volume = v and mass = m
So, the relation between volume and mass will take the form:
v = km
where k is constant and can be calculated as follow:
when m = </span><span>34.932 , and v = 4.1 ⇒⇒⇒ k = v/m = 0.117371
</span>when m = 47.712<span> , and v = 5.6 ⇒⇒⇒ k = v/m = </span>0.117371
when m = 61.344 , and v = 7.2 ⇒⇒⇒ k = v/m = <span>0.117371
when m = </span>99.684 , and v = 11.7 ⇒⇒⇒ k = v/m = <span>0.117371
∴ v = 0.117371 m
</span>
For v =<span>15.3
∴ m = v/k = 15.3/0.117371 = 130.356 </span><span>gram
</span>The mass of a piece of this metal that has a volume of 15.3 cubic centimeters ≈ 130.4 gram (<span>round to the nearest tenth</span>)
Answer:
The number c is 2.
Step-by-step explanation:
Mean Value Theorem:
If f is a continuous function in a bounded interval [0,4], there is at least one value of c in (a,b) for which:
![f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx](https://tex.z-dn.net/?f=f%28c%29%20%3D%20%5Cfrac%7B1%7D%7Bb-a%7D%5Cint%5Climits%5Ea_b%20%7Bf%28x%29%7D%20%5C%2C%20dx%20)
In this problem, we have that:
![f(x) = x, a = 0, b = 4](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%2C%20a%20%3D%200%2C%20b%20%3D%204)
So ![f(c) = c](https://tex.z-dn.net/?f=f%28c%29%20%3D%20c)
----------
![f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx](https://tex.z-dn.net/?f=f%28c%29%20%3D%20%5Cfrac%7B1%7D%7Bb-a%7D%5Cint%5Climits%5Ea_b%20%7Bf%28x%29%7D%20%5C%2C%20dx)
![c = \frac{1}{4-0}\int\limits^0_4 {x} \, dx](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7B1%7D%7B4-0%7D%5Cint%5Climits%5E0_4%20%7Bx%7D%20%5C%2C%20dx)
![c = \frac{1}{4-0}*8](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7B1%7D%7B4-0%7D%2A8)
![c = 2](https://tex.z-dn.net/?f=c%20%3D%202)
The number c is 2.
Expression with parenthesis: = 2 ( l + w)
Expression without parenthesis = 2l + 2w
The property we used is known as "Distributive Property"
Let, width = w
Length = w + 70
Perimeter would be: P = 2(w+70+w)
p = 2(2w+70)
p = 4w + 140
Hope this helps!
Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).
n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14
> is greater than
< is less than