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2 years ago

Write a rule for the nth term of the geometric sequence if r=1/4 and a =6

Mathematics

1 answer:

Shalnov [3]2 years ago

5 0

Answer:

a(n) = a(1)*(1/4)^(n-1)

Step-by-step explanation:

The first term is a(1) = 6, and the common ratio is r = 1/4.

Then the general formula for this sequence is

a(n) = a(1)*(1/4)^(n-1)

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Answer:

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Step-by-step explanation:

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Anna007 [38]

n 1 2 3 4 5 6

f(n) 1033 932 831 730 629 528

First term (a₁): 1033 Common difference (d): -101

Explicit rule: $a_{n} = 1134 - 101n$ Recursive rule: $a_{n} = a_{n-1} - 101$

$a_{n} = a_{1} + d(n - 1)$

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$a_{n} = 1134 - 101n$

***********************************************************************************

n 1 2 3 4 5 6

f(n) -39 -29 -19 -9 9 19

First term (a₁): -39 Common difference (d): +10

Explicit rule: $a_{n} = -49 + 10n$ Recursive rule: $a_{n} = a_{n-1} + 10$

$a_{n} = a_{1} + d(n - 1)$

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n 1 2 3 4 5 6

f(n) 3.75 2.5 1.25 0 -1.25 -2.5

First term (a₁): 3.75 Common difference (d): -1.25

Explicit rule: $a_{n} = 5 - 1.25n$ Recursive rule: $a_{n} = a_{n-1} - 1.25$

$a_{n} = a_{1} + d(n - 1)$

$a_{n} = 3.75 - 1.25(n - 1)$

$a_{n} = 3.75 - 1.25n + 1.25$

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Step-by-step explanation:

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