![{ \red{ \bold{cos \: y \: }}}](https://tex.z-dn.net/?f=%7B%20%5Cred%7B%20%5Cbold%7Bcos%20%5C%3A%20y%20%20%5C%3A%20%7D%7D%7D)
Step-by-step explanation:
![{ \green{ \tt{ \frac{1 \: + \: \cos \: y \: }{1 \: + \: \sec \: y \: }}}} \: → {eq}^{n} (1)](https://tex.z-dn.net/?f=%7B%20%5Cgreen%7B%20%5Ctt%7B%20%5Cfrac%7B1%20%20%5C%3A%20%2B%20%20%20%5C%3A%20%5Ccos%20%5C%3A%20y%20%5C%3A%20%7D%7B1%20%20%5C%3A%20%2B%20%20%20%5C%3A%20%5Csec%20%5C%3A%20y%20%5C%3A%20%7D%7D%7D%7D%20%5C%3A%20%E2%86%92%20%7Beq%7D%5E%7Bn%7D%20%281%29)
But, as you know that
![{ \blue{ \tt{sec \: y \:}}} = { \green{ \tt{\frac{1}{ \ \cos \: y }}}}](https://tex.z-dn.net/?f=%7B%20%5Cblue%7B%20%5Ctt%7Bsec%20%5C%3A%20y%20%5C%3A%7D%7D%7D%20%20%3D%20%20%20%7B%20%5Cgreen%7B%20%5Ctt%7B%5Cfrac%7B1%7D%7B%20%5C%20%5Ccos%20%5C%3A%20y%20%7D%7D%7D%7D%20)
Then the equation (1) becomes
![{ \green{ \tt{ \frac{1 \: + \: cos \: y }{1 \: + \: \frac{1}{cos \: y} }}}} \:](https://tex.z-dn.net/?f=%7B%20%5Cgreen%7B%20%5Ctt%7B%20%5Cfrac%7B1%20%20%5C%3A%20%2B%20%5C%3A%20cos%20%5C%3A%20y%20%7D%7B1%20%20%5C%3A%20%20%2B%20%20%20%5C%3A%20%20%5Cfrac%7B1%7D%7Bcos%20%5C%3A%20y%7D%20%7D%7D%7D%7D%20%5C%3A%20%20)
Multiply Numerator and Denominator by ![\frac{cos \: y}{cos \: y}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bcos%20%5C%3A%20y%7D%7Bcos%20%5C%3A%20y%7D%20)
then,
![{ \green{ \tt{( \frac{cos \: y}{cos \: y})}}} \: { \green{ \tt{ \frac{1 \: + \: cos \: y}{1 \: + \: \frac{1}{cos \: y}}}}}](https://tex.z-dn.net/?f=%7B%20%5Cgreen%7B%20%5Ctt%7B%28%20%5Cfrac%7Bcos%20%5C%3A%20y%7D%7Bcos%20%5C%3A%20y%7D%29%7D%7D%7D%20%5C%3A%20%7B%20%5Cgreen%7B%20%5Ctt%7B%20%5Cfrac%7B1%20%20%5C%3A%20%20%2B%20%20%5C%3A%20cos%20%5C%3A%20y%7D%7B1%20%5C%3A%20%20%2B%20%20%5C%3A%20%20%5Cfrac%7B1%7D%7Bcos%20%5C%3A%20y%7D%7D%7D%7D%7D%20)
![= { \green{ \tt{ \frac{cos \: y \: + \: {cos}^{2} \: y }{cos \: y \: + \: 1 }}}}](https://tex.z-dn.net/?f=%20%3D%20%7B%20%5Cgreen%7B%20%5Ctt%7B%20%5Cfrac%7Bcos%20%5C%3A%20y%20%5C%3A%20%20%2B%20%20%5C%3A%20%20%7Bcos%7D%5E%7B2%7D%20%5C%3A%20y%20%7D%7Bcos%20%5C%3A%20y%20%5C%3A%20%2B%20%20%5C%3A%201%20%7D%7D%7D%7D)
take cos y as common, then
![{ \green{ \tt{cos \: y}}} \: { \green{ \tt( \frac{1 \: + \: cos \: y}{cos \: y \: + \: 1} )}}](https://tex.z-dn.net/?f=%7B%20%5Cgreen%7B%20%5Ctt%7Bcos%20%5C%3A%20y%7D%7D%7D%20%5C%3A%20%7B%20%5Cgreen%7B%20%5Ctt%28%20%5Cfrac%7B1%20%5C%3A%20%20%2B%20%20%5C%3A%20cos%20%5C%3A%20y%7D%7Bcos%20%5C%3A%20y%20%5C%3A%20%20%2B%20%20%5C%3A%201%7D%20%29%7D%7D)
Here, (1+cos y/cos y + 1) gets cancelled.
Then the remaining answer is cos y.
c. 4.6
21 X .22= 4.6
Calculating the variance requires finding the product of 21 and 22%. To make this easier we convert 22% into it's decimal form and construct the equation. To back check this answer we can use 10% of 21 voters which equals 2.1% then double that amount to reach 4.2%, knowing that we now have a close approximation of the variance we can eliminate answers a, b, and d, leaving c as the only logical choice.
I need a picture for me to answer
Answer: u= ( 4342.08, 5145.92).
Step-by-step explanation: the population mean is estimated using the sample by the formulae assuming a 95% confidence level
u = x' + Zα/2 * (√σ/n) or x' - Zα/2 * (√σ/n)
u = estimated population mean
x' = sample mean = 4744
n = sample size =8
σ = sample standard deviation. = 580
α = level of significance = 1- confidence level = 1-0.95= 0.05
Zα/2 = z score from the normal distribution table for a 2 tailed test = 1.96
First boundary value for interval
u = 4744 + 1.96 ( 580/√8)
u = 4744 + 1.96 * (205.0609)
u = 4744 + 401.92
u = 5145.92
Second boundary value for interval
u = 4744 - 1.96 ( 580/√8)
u = 4744 - 1.96 * (205.0609)
u = 4744 - 401.92
u = 4342.08
Thus the confidence interval for population mean is
u= ( 4342.08, 5145.92).
Answer:
a would have an 75% chance
Step-by-step explanation:
Because you would go through and count the letters and then find the probable percentage.