3 years ago

I have this question and I need it done bad... Help please? Picture included I was never taught matrix

1 answer:

6 0

Multiply the numbers on the major axis which are 2 and -9 to get -18. Subtract from that 3*4 = 12. So -18-12 = -30. That's the determinant.

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Sunny_sXe [5.5K]

Answer:

as written: 7x^2

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Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

$\dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2$

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

21x^3/(3x^-1)

then the simplification is ...

$\dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4$

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^b/a^c = a^(b-c)

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