For both of them you just make them into fraction.
For #2

and then you simplify it
36. ÷12 3
-----. =. --------
120. ÷12 10
After this you want to change the fraction to a percentage.Percentage are out of 100
so you simply will multiply by 10 to the top and bottom
3. 30
----. * 10 =. -----. = 30%
10. 100
The answer is 30%
For number #3
you simply put 63 over 240
63
-----
240



21
----
80
is that answer because it can't be simplified
after that
There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
Learn more about Word Problems from
brainly.com/question/21405634
Answer:
yes
Step-by-step explanation:
|-12| = |12| they always equal to 12
Answer: x=4
Step-by-step explanation:
The perimeter´s formula for this kind of polygons is
The triangle perimeter would be:
(x+2)+(x+3)+(x+3)
And the rectangle:
(x+2)+(x+2)+x+x
For them to have the same value, we should equal them:
(x+2)+(x+3)+(x+3)=(x+2)+(x+2)+x+x
Working with this:
3x+8=4x+4
x=4